Answer:
d
Explanation:
p is pressure, v is vo;lume, t is temperature, r is ideal gas contstant, therefore n is the moles
P orbitals have 3 sub-shells, each of which can hold one pair of electrons that have opposing spins. This leads to p orbitals holding a maximum of 6 electrons
The answer for the following problem is explained below.
- <u><em>Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.</em></u>
Explanation:
Given:
mass of methane = 6.00 × 10^-3 grams
+
→
+
Firstly balance the following equation:
Before balancing the equation:
→ 
After balancing the equation:
→ 
where;
represents methane molecule
represents oxygen molecule
represents carbon dioxide molecule
represents water molecule
+2
→
+ 2
16 grams of methane → 44 grams of carbon dioxide
6 × 10^-3 grams of methane → ?
= 
= 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.
<u><em>Therefore 16.5 × 10^-3 grams of carbon dioxide is produced from the complete combustion.</em></u>
For the first question, i think the correct answer is the third option. When a gas is formed, it is <span>the most conclusive in determining whether a chemical reaction has taken place given that none of your reactants is a gas.
For the second question, the statement is true.
For the third question, the correct answer is the last option.</span>
Answer:
[N2] = [O2] = 0.841M
And [NO] = 0.00172M
Explanation:
The equilibrium constant of this reaction, Kc, is:
Kc = 2400 = [N2] [O2] / [NO]²
<em>Where [] are the equilibrium concentration of each specie.</em>
<em />
The initial concentration of [N2] = [O2] = 0.850M. The equilibrium will shift to the left in order to produce NO. The equilibrium concentrations are:
[N2] = [O2] = 0.850M - X
And [NO] = 2X
Replacing:
2400 = [0.850-X]² / [2X]²
9600X² = 0.7225 - 1.7 X + X²
0 = 0.7225 - 1.7 X - 9599X²
Solving for X:
X = -0.0088M. False solution, there is no negative concentrations.
X = 0.00859M. Right solution.
Replacing:
[N2] = [O2] = 0.850M - 0.00859M
And [NO] = 2*0.00859M
[N2] = [O2] = 0.841M
And [NO] = 0.00172M