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Nonamiya [84]
3 years ago
12

A neutral atom has 8 electrons and 8 neutrons. Which of the following correctly represents the atom? A) carbon-16 B) oxygen-16 C

) oxygen-24 D) oxygen-8 E) sultry-8
Chemistry
2 answers:
Semmy [17]3 years ago
8 0
D - oxygen
It is the 8th element in the periodic table. 8 electrons, 8 neutrons when it is in its neutral state
bija089 [108]3 years ago
6 0

Answer:

D

Explanation:

Oxygen is the 8th element in the periodic table. This means that oxygen has 8 protons and 8 electrons. In order to get the number of neutrons you take the atomic weight in this case 15.9999~16 and you subtract it by the number of protons (16-8).

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Who discovered significance of 6.022 x 10 to the 23 power
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I hope this helps!
6 0
3 years ago
If I have 21 liters of gas held at a pressure of 78 atm and a temperature of 900 K, what will
shusha [124]

Answer:

30.33L

Explanation:

Using Boyle's law which states that the volume of a given mass of gas is inversely proportional to the pressure, provided temperature remains constant  and Charles law states that the volume of a given mass of gas is directly proportional to the temperature provided the pressure remains constant

P1V1/T1 = P2V2/ T2

P1 =  78atm, V1 = 21L , T1 = 900K

P2 = 45atm, V2 = ? , T2 =750K

78× 21 / 900 = 45×V2 / 750

1638/900 = 45 V2 / 750

1638×750 = 900×45V2

1228500 = 40500V2

Divide both sides by 40500

1228500÷40500= V2

V2 = 30.33L

I hope this was helpful, please mark as brainliest

6 0
3 years ago
The radius of a vanadium atom is 130 pm. How many vanadium atoms would have to be laid side by side to span a distance of 1.30 m
monitta

Answer:

5 000 000 (5 million atoms)

Explanation:

Let us assume that a vanadium atom has a spherical shape.

diameter of a sphere = 2 x radius of the sphere

Thus,

Radius of a vanadium atom = 130 pm

                                              = 130 x 10^{-12} m

The diameter of a vanadium atom = 2 x radius

                                                         = 2 x 130 x 10^{-12}

                                               = 260 x 10^{-12} m

Given a distance of 1.30 mm = 1.30 x 10^{-3} m,

The number of vanadium atoms required to span the distance = \frac{1.3*10^{-3} }{260*10^{-12} }

                                                  = 5000000

Therefore, the number of vanadium atom that would span a distance of 1.30 mm is 5 million.

3 0
3 years ago
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