|a| = b gives
a =b or a = -b
so,
|-x| = -10
gives
-x = -10 or -x = 10
x = 10, -10
now let us verify,
when x = 10, |-10| = +10 and it is not = -10
so, x= 10 is NOT a solution.
when x = -10, |-(-10)| = |10| = 10 and it is not = -10
so, x= -10 is NOT a solution.
hence, this equation does not have a solution.
If we know that |...| can never be negative, we can directly deduce that this equation does not have any solution.
Answer:
1 2/9 minutes faster
Step-by-step explanation:
Take the larger number and subtract the smaller number
8 5/9 minutes - 7 1/3 minutes
Get a common denominator
8 5/9 - 7 1/3 *3/3
8 5/9 - 7 3/9
1 2/9 minutes faster
The correct answer:
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Explanation:
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Assuming you mean:
" √(9a²) + (√49b) − a + √b " ;
Simplify the expression:
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Note that: " √(9a²) = 3a " ;
"√(49b) = 7√b " ;
And we write the expression
→ " 3a + 7√b − a + √b " ;
Combine the "like terms:
" + 3a − a = 2a " ;
" + 7√b + 1√b = 8√b " ;
Rewrite:
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" 2a + 8√b " ; which is: Answer choice: [C]: " 2a + 8√b " .
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The numbers listed are:
3, 3 ,3 ,7 ,8 ,8 ,11 ,11 ,13 ,14 ,15 ,17, 18, 19, 21, 23, 23 ,25,27, 28, and 29.
The number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
<h3>How to determine the number of ways</h3>
Given the word:
ESTABROK
Then n = 8
p = 6
The formula for permutation without restrictions
P = n! ( n - p + 1)!
P = 8! ( 8 - 6 + 1) !
P = 8! (8 - 7)!
P = 8! (1)!
P = 8 × 7 × 6 × 5 × 4 × 3 × 2 × 1 × 1
P = 40, 320 ways
Thus, the number of ways in which the name 'ESTABROK' can be made with no restrictions is 40, 320 ways.
Learn more about permutation here:
brainly.com/question/4658834
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