What is the distance between -60 and -10 0n a number line?
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Answer: 2.508
Step-by-step explanation:
As per give , we have
Sample size : n= 23
Degree of freedom : df= n-1=22
significance level :
Since , the sample size is small (n<30) and population standard deviation is unknown.
So , we use t-test.
For confidence interval , we find two-tailed test value.
Critical t-value :
[using students's t-critical value table]
Hence, the critical value that should be used in constructing the confidence interval = 2.508