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valentina_108 [34]
2 years ago
8

What is the distance between -60 and -10 0n a number line?

Mathematics
1 answer:
JulsSmile [24]2 years ago
5 0

Answer: 70

Step-by-step explanation: The absolute value of a number is its distance from zero on the number line. Since absolute value is a distance, it is always greater than or equal to zero.

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Combing like terms -14+12+9z-16z =
tigry1 [53]

Answer:

-6/7

Step-by-step explanation:

-14+12+9z-16z=0

-6-7z=0

Add 7z to both sides

-6=7z

Divide both sides by 7

z=-6/7

Therefore the value for z is -6/7

5 0
2 years ago
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I need help its math
Degger [83]

Given: w²+9=6w [0, 3, 6, 9]

We need to substitute each number for w and find which works

Sub Zero: 0²+9=6×0

Simplify: 9=0. 9 does not equal 0, so it is not 0

Sub Three: 3²+9=6×3

Simplify: 9+9=18

Addition: 18=18

The statement 18=18 is true, therefore we have our answer.

Answer: The second option is correct. 3 would be the correct number to substitute to make the equation correct.

3 0
3 years ago
What information can be used to compare linear<br> relationships? Explain why.
almond37 [142]

Answer:

Step-by-step explanation:

The slope and the y intercept (you can tell there linear if the slope is the same and the y-intercepts are different).

3 0
3 years ago
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(4n⁴-8n+4) - (8n²+4n⁴+1) <br> How do I simplify this expression?
Kobotan [32]

Answer:

-4n^4-4n^2-8n+3

Step-by-step explanation:

you combine the like terms

8 0
3 years ago
An engineer is planning a new water pipe installation. The circular pipe has a diameter of d=20\text{ cm}d=20 cmd, equals, 20, s
aivan3 [116]

Answer: The answer is 314.28 cm² (approx.).


Step-by-step explanation:  Given that an engineer is going to install a new water pipe. The diameter of this circular pipe is, d = 20 cm.

We need to find the area 'A' of the circular cross-section of the pipe.

Given, diameter of the circular section is

\textup{d}=20~\textup{cm}.

So, the radius of the circular cross-section will be

\textup{r}=\dfrac{\textup{d}}{2}=\dfrac{20}{2}=10~\textup{cm}.

Therefore, cross-sectional area of the pipe is

\textup{A}=\pi \textup{r}^2=\dfrac{22}{7}(10)^2=\dfrac{2200}{7}=314\dfrac{2}{7}=314.28~.~.~.~\textup{cm}^2.

Thus, the answer is 314.28 cm² (approx.).

4 0
3 years ago
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