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frosja888 [35]
3 years ago
8

What are the solutions to x^2-13x+30

Mathematics
1 answer:
BlackZzzverrR [31]3 years ago
4 0
ax^2+bx+c=0  \\ \\
x^2-13x+30 = 0 \\ \\ D=b^2-4ac = 169-120=\sqrt{49} =7 \\ \\ x_{1/2} =  \frac{-b^2+/-\sqrt{D}}{2a} = \frac{13+/-7}{2*1} \\ \\ x_1 = \frac{13+7}{2} = 10 \\ \\ x_2 = \frac{13-7}{2} = 3
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The sum of 3 times the value of x and 2 is equal to four less than five times the value of x. Which equation can be used to find
bonufazy [111]

The question has omitted  options but i will solve, so you will just check my answer from the options you have.

Answer: The equation  to find the value of x = 3x+ 2= 5x-4

The value of x= 3

Step-by-step explanation:

Step 1

The sum of 3 times the value of x and 2 is equal to four less than five times the value of x can be expressed as

3x+ 2= 5x-4

Step 2

Solving this equation  to find the value of x , we have that

3x+ 2= 5x-4

3x-5x= -4-2

-2x= -6

x= -6/-2

x=3

5 0
3 years ago
Find the LCM and HCF of 110 and 220 by prime factorization what do you observe....pls answer this ​
ElenaW [278]

Answer: Check if numbers are prime. Composite numbers prime factorization (decomposing, breaking numbers down to prime factors). Inscribe them as a product of prime factors, in exponential notation.

8 0
3 years ago
I need help with #47 to #50 ASAP…. Please help me with it
Ksenya-84 [330]

Step-by-step explanation:

a triangular number n is the sum of all natural numbers <= n.

t1 = 1

t2 = 1+2 = 3

t3 = 1+2+3 = 6

t4 = 1+2+3+4 = 10

...

so,

tn = tn-1 + n

47.

1×8 + 1 = 9 is a square number.

3×8 + 1 = 25 is a square number

6×8 + 1 = 49 is a square number

10×8 + 1 = 81 is a square number

48.

1/3 = 0 remainder 1

3/3 = 1 remainder 0

6/3 = 2 remainder 0

10/3 = 3 remainder 1

15/3 = 5 remainder 0

21/3 = 7 remainder 0

28/3 = 9 remainder 1

so, there seems to be a pattern 1 0 0 1 0 0 1 0 0 1 ...

49.

1/4 = 0 remainder 1

4/4 = 1 remainder 0

9/4 = 2 remainder 1

16/4 = 4 remainder 0

25/4 = 6 remainder 1

36/4 = 9 remainder 0

49/4 = 12 remainder 1

so, there seems to be a pattern 1 0 1 0 1 0 1 0 1 0 1 ...

50.

polygonal numbers is the real name for this.

the formula for dimensions = 5 is

(3n² − n)/2

for dimensions = 6 it is

2n² - n

so, dimensions=5 (and therefore dividing also by 5) we get the remainders

1/5 = 0 remainder 1

5/5 = 1 remainder 0

12/5 = 2 remainder 2

22/5 = 4 remainder 2

35/5 = 7 remainder 0

51/5 = 10 remainder 1

70/5 = 14 remainder 0

92/5 = 18 remainder 2

117/5 = 23 remainder 2

145/5 = 29 remainder 0

here the pattern is 1 0 2 2 0 1 0 2 2 0 1 0 2 2 0 ...

dimensions=6 (and therefore dividing also by 6) we get the remainders

1/6 = 0 remainder 1

6/6 = 1 remainder 0

15/6 = 2 remainder 3

28/6 = 4 remainder 4

45/6 = 7 remainder 3

66/6 = 11 remainder 0

91/6 = 15 remainder 1

120/6 = 20 remainder 0

153/6 = 25 remainder 3

190/6 = 31 remainder 4

231/6 = 38 remainder 3

276/6 = 46 remainder 0

325/6 = 54 remainder 1

here the pattern is 1 0 3 4 3 0 1 0 3 4 3 0 1 0 3 4 3 0 ...

8 0
3 years ago
Which of the following values when placed in the ten's place for the number 1_1 will make it a prime number?
Sloan [31]
The answer is 181.

Ans: 8
6 0
3 years ago
Read 2 more answers
What is the simplified form of x plus 1 over x squared plus x minus 6 ÷ x squared plus 5x plus 4 over x plus 4 ?
Mumz [18]

Answer:

1 / (x-2)(x+3)

Step-by-step explanation:

Given in the question the expression:

(x + 1) / (x² + x - 6) ÷  (x² + 5x + 4) / (x+4)

factorisation of (x² + x - 6) = (x-2)(x+3) by using quadratic equation

(x + 1) / (x-2)(x+3) ÷  (x² + 5x + 4) / (x+4)

Taking reciprocal to convert ÷ into ×

(x + 1) / (x-2)(x+3) x (x+4) / (x² + 5x + 4)

factorisation of (x² + 5x + 4) =  (x+1)(x+4) by using quadratic equation

(x + 1) / (x-2)(x+3)    x    (x+4) / (x+1)(x+4)

cancel (x + 1) from both expression

1 / (x-2)(x+3)    x    (x+4) / (x+4)

cancel (x+4)

1 / (x-2)(x+3)  Simplified form

5 0
3 years ago
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