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ryzh [129]
3 years ago
9

Evaluate fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5.

Mathematics
2 answers:
Over [174]3 years ago
6 0
Remember \sqrt[n]{x^m} =x^ \frac{m}{n} and
(x^m)(x^n)=x^{m+n} and
\frac{x^m}{x^n}=x^{m-n} and
(x^m)^n=x^{mn}

so

( \sqrt[4]{9})( \frac{ \sqrt{9} }{\sqrt[4]{9^5}})=
( \sqrt[4]{9})( \frac{ \sqrt{2}{3^2} }{9^\frac{5}{4}})=
( \sqrt[4]{9})( 3^\frac{2}{2} }{9\sqrt[4]{9}})=
\frac{3}{9}=
\frac{1}{3}
Naya [18.7K]3 years ago
4 0
It would be 0.33333333333
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Step-by-step explanation:

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Solve for x. 3^x−1=9^x+2 <br> Enter your answer in the box.
slava [35]

Answer:

-5 =x

Step-by-step explanation:

3^(x-1) = 9^(x+2)

Replace 9 with 3^2

3^(x-1) = 3^2^(x+2)

We know that a power to a power means the powers are multiplied

a^b^c = a^(b*c)

3^(x-1) = 3^(2x+2)

When the bases are the same, the powers have to be the same

x-1 = 2x+4

Subtract x from each side

x-x-1 =2x-x+4

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Subtract 4 from each side

-1-4 =x+4-4

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4 0
3 years ago
Which of the following is an extraneous solution of (45-3x)^1/2=x-9?
Iteru [2.4K]

Answer:

C. x =3

Step-by-step explanation:

Extraneous solution is that root of a transformed equation that doesn't satisfy the equation in it's original form because it was excluded from the domain of the original equation.

Let's solve the equation first

\sqrt{45-3x} = x-9\\Taking\ square\ on\ both\ sides\\{(\sqrt{45-3x})}^2 = {(x-9)}^2\\45-3x = x^2-18x+81\\0 = x^2-18x+81-45+3x\\x^2-15x+36 = 0\\x^2-12x-3x+36 = 0\\x(x-12)-3(x-12) = 0\\(x-3)(x-12)\\x-3 = 0\\=> x =3\\x-12 = 0\\x = 12\\We\ will\ check\ the\ solutions\ one\ by\ one\\So,\\for\ x=3\\\sqrt{45-3(3)} = 3-9\\\sqrt{45-9} = -6\\\sqrt{36}= -6\\6\neq -6\\For x=12\\\sqrt{45-3(12)} = 12-9\\\sqrt{45-36} = 6\\\sqrt{36}= 6\\6=6

Hence, we can conclude that x=3 is an extraneous solution of the equation ..

3 0
3 years ago
What is the equation of the parabola?
Neporo4naja [7]

Answer:

y = -1/8 x² + 5

Step-by-step explanation:

Parabola opens vertically and vertex (h,k) = (0,5), pass point (4,3)

basic formula: y = a(x - h)² + k

y = a (x-0)² + 5

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equation: y = -1/8 x² + 5

check: pass another point (-4,3)

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5 0
3 years ago
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