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ryzh [129]
3 years ago
9

Evaluate fourth root of 9 multiplied by square root of 9 over the fourth root of 9 to the power of 5.

Mathematics
2 answers:
Over [174]3 years ago
6 0
Remember \sqrt[n]{x^m} =x^ \frac{m}{n} and
(x^m)(x^n)=x^{m+n} and
\frac{x^m}{x^n}=x^{m-n} and
(x^m)^n=x^{mn}

so

( \sqrt[4]{9})( \frac{ \sqrt{9} }{\sqrt[4]{9^5}})=
( \sqrt[4]{9})( \frac{ \sqrt{2}{3^2} }{9^\frac{5}{4}})=
( \sqrt[4]{9})( 3^\frac{2}{2} }{9\sqrt[4]{9}})=
\frac{3}{9}=
\frac{1}{3}
Naya [18.7K]3 years ago
4 0
It would be 0.33333333333
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The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

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95% confidence interval

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The margin of error is:

M = T\frac{s}{\sqrt{n}} = 1.989\frac{1.2}{\sqrt{85}} = 0.26

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The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.26 = 4.24 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.26 = 4.76 days

The 95% confidence interval for the population's mean length of vacation, in days, is (4.24, 4.76).

92% confidence interval:

Following the sample logic, the critical value is 1.772. So

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The lower end of the interval is the sample mean subtracted by M. So it is 4.5 - 0.23 = 4.27 days

The upper end of the interval is the sample mean added to M. So it is 4.5 + 0.23 = 4.73 days

The 92% confidence interval for the population's mean length of vacation, in days, is (4.27, 4.73).

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3 years ago
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