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vladimir1956 [14]
3 years ago
13

Which of the following systems of equations has no solution?

Mathematics
2 answers:
UkoKoshka [18]3 years ago
8 0
The system of equations that has no solution are the equations that has the same slope which means they are parallel and do not intersect with each other at any point. From the choices, the correct answer is option D.
<span>
</span><span> 7y = 5x − 10
y = (5/7) - 10/7
slope = 5/7

10x − 14y = 8</span>
-14y = -10x + 8
y = (5/7) - 4/7
slope = 5/7
Law Incorporation [45]3 years ago
7 0
For option d:
5x - 7y = 10 . . . . . (1)
10x - 14y = 8 . . . . (2)

(1) x 2 => 10x - 14y = 20 . . . . . (3)

(2) - (3) => 0 = -14              [not possible]

Therefore, the set of equations in option d, has no solutions.
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Translate 22% of b into an expression
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Answer:

11/50b

Step-by-step explanation:

22% of b = 22/100×b

= 11/50b

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Snowcat [4.5K]
15/10 = 18-x/x is the ratio of the larger to the smaller triangle

Cross multiply:
15x = 10(18 - x)
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25x = 180
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6 0
3 years ago
1Y, the number of accidents per year at a given intersection, is assumed to have a Poisson distribution. Over the past few years
miss Akunina [59]

Answer:

The probability that the intersection will come under the emergency program is 0.1587.

Step-by-step explanation:

Lets divide the problem in months rather than in years, because it is more suitable to divide the period to make a better approximation. If there were 36 accidents in average per year, then there should be 3 accidents per month in average. We can give for the amount of accidents each month a Possion distribution with mean 3 and variance 3.

Since we want to observe what happen in a period of one year, we will use a sample of 12 months and we will take its mean. We need, in average, more than 45/12 = 3.75 accidents per month to confirm that the intersection will come under the emergency program.

For the central Limit theorem, the sample mean will have a distribution Normal with mean 3 and variance 3/12 = 0.25; thus its standard deviation is √0.25 = 1/2.

Lets call the sample mean distribution X. We can standarize X obtaining a standard Normal random variable W with distribution N(0,1).

W = \frac{X-\mu}{\sigma} = \frac{X-3}{1/2} = 2x-6

The values of \phi , the cummulative distribution function of W, can be found in the attached file. We are now ready to compute the probability of X being greater than 3.75, or equivalently, the probability than in a given year the amount of accidents is greater than 45, leading the intersection into an emergency program

P(X > 3.75) = P(2X-6 > 2*3.75-6) = P(W > 1) = 1-\phi(1) = 1-0.8413 \\= 0.1587

Download pdf
7 0
3 years ago
comparison: Sara has three times as many pencil erasers as Sam together they have 28 erasers how many erasers does Sara have
IgorC [24]
Sara has 21
Sam has 7
7x3= 21+ sams 7= 28
5 0
3 years ago
Read 2 more answers
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