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Katena32 [7]
3 years ago
6

Identify the function shown in the graph

Mathematics
2 answers:
hram777 [196]3 years ago
3 0

Answer:

C

Step-by-step explanation:

The line crosses the y-axis at 3, and has a slope of -1/5. You can use the formula y=mx+b where m represents the slope and b is the point at which the line crosses the y-axis.

Illusion [34]3 years ago
3 0
C. y=-1/5x+3 is the answer
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The response variable is the one on the left of the equal sign, weight.


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3 years ago
What is the standard form polynomial representing the volume of this shipping container?
harina [27]

Answer:

Volume = (24x⁵ + 78x⁴ - 147x³ - 624x² - 360x)

Step-by-step explanation:

Container given in the picture is in the shape of a cuboid.

And volume of a cuboid is measured by the expression,

Volume of a cuboid = Length × width × height

Now substitute the measure of the container's dimensions given in the picture

Volume = (4x² + 3x)(x²- 8)(6x + 15)

             = [(4x² + 3x)(x²- 8)](6x + 15)

             = [4x²(x² - 8) + 3x(x² - 8)](6x + 15)

             = (4x⁴ - 32x² + 3x³ - 24x)(6x + 15)

             = (4x⁴ + 3x³ - 32x² - 24x)(6x + 15)

             = 6x(4x⁴ + 3x³ - 32x² - 24x) + 15(4x⁴ + 3x³ - 32x² - 24x)

             = 24x⁵+ 18x⁴ - 192x³ - 144x² + 60x⁴ + 45x³ - 480x² - 360x

             = 24x⁵ + 78x⁴ - 147x³ - 624x² - 360x

8 0
3 years ago
Read 2 more answers
Compare the two statements below and decide if the phrase: "In a plane," needs to be included in order to make a true statement.
mel-nik [20]

by any chance do you go to a higl school in Conroe bc I’m taking that exact test on canvas

Step-by-step explanation:

3 0
3 years ago
Find m-1(x) if m(x) = x+3.​
lawyer [7]

Step-by-step explanation:

m(x) = x+3

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5 0
3 years ago
What is the derivative of ln(lnx^3)
chubhunter [2.5K]

the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

<u>Step-by-step explanation:</u>

Here we have to find the derivative of ln(lnx^3) , Let's find out:

We have , ln(lnx^3) , Let's differentiate it w.r.t x :

⇒ \frac{d(ln(lnx^3))}{dx}

Let lnx^3 = u

⇒ \frac{d(ln(u))}{dx}

⇒ \frac{1}{u} (\frac{d(u)}{dx} )

⇒ \frac{1}{u} (\frac{d(ln(x^3))}{dx} )

Let x^3=v

⇒ \frac{1}{u} (\frac{d(ln(v))}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(v)}{dx} )

⇒ \frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )            

⇒ 3x^2(\frac{1}{u})(\frac{1}{v} )

Putting value of u & v we get:

⇒ 3x^2(\frac{1}{lnx^3})(\frac{1}{x^3} )

⇒ \frac{3}{x(lnx^3)}    { lnx^n = n(lnx)  }

⇒ \frac{3}{3x(lnx)}

⇒ \frac{1}{x(lnx)}

Therefore , the derivative of ln(lnx^3) is \frac{1}{x(lnx)} .

6 0
3 years ago
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