Answer:
def calculate_pay(total_worked_hours, rate_per_hour):
if total_worked_hours > 40:
return (40 * rate_per_hour) + ((total_worked_hours - 40) * 2 * rate_per_hour)
else:
return total_worked_hours * rate_per_hour
Explanation:
- Create the calculate_pay function that takes 2 parameters.
- Inside the function check whether the total_worked_hours is greater than 40 and then return the pay by calculating with the help of formula for work over 40 hours.
- Otherwise return the pay by multiplying the total_worked_hours with rate_per_hour.
The first thing we are going to do is find the equation of motion:
ωf = ωi + αt
θ = ωi*t + 1/2αt^2
Where:
ωf = final angular velocity
ωi = initial angular velocity
α = Angular acceleration
θ = Revolutions.
t = time.
We have then:
ωf = (7200) * ((2 * pi) / 60) = 753.60 rad / s
ωi = 0
α = 190 rad / s2
Clearing t:
753.60 = 0 + 190*t
t = 753.60 / 190
t = 3.97 s
Then, replacing the time:
θ1 = 0 + (1/2) * (190) * (3.97) ^ 2
θ1 = 1494.51 rad
For (10-3.97) s:
θ2 = ωf * t
θ2 = (753.60 rad / s) * (10-3.97) s
θ2 = 4544,208 rad
Number of final revolutions:
θ1 + θ2 = (1494.51 rad + 4544.208 rad) * (180 / π)
θ1 + θ2 = 961.57 rev
Answer:
the disk has made 961.57 rev 10.0 s after it starts up
Answer:
A. 4 CPUs and 6 megabyte cache memory
B. 1.3157 x10^-9 nanoseconds
Explanation:
The Intel core i5 7500 is a seventh generation central processing unit with a 4 CPU core and a 6 megabyte cache memory. It executes task at a clock cycle of 5 clock cycle at a speed of 3.8 GHz.
The relationship between frequency and clock cycle is,
Clock cycle = 1 / ( frequent).
So, One clock cycle = 1 / 3.8 GHz
= 0.3 x10^-9
For five clock cycles = 5 x 0.3 x10^-9
= 1.3157 x10^-9 nanoseconds.
