The correct answer is letter B. Application Software. Word Processing software, spreadsheet software, database software, and presentation software are examples of Application software. These are applications that are mostly output based.
Answer:
Replace /* Your code goes here */ with
for(i =0; i<NUM_VALS; i++)
{
printf("%d", origList[i]*offsetAmount[i]);
printf(";");
}
Explanation:
The first line is an iteration statement iterates from 0 till the last element in origList and offsetAmount
for(i =0; i<NUM_VALS; i++)
{
This line calculates and print the product of element in origList and its corresponding element in offsetAmount
printf("%d", origList[i]*offsetAmount[i]);
This line prints a semicolon after the product has been calculated and printed
printf(";");
Iteration ends here
}
Answer:
Hi Riahroo! This is a good question on the concept of relational databases.
We can normalize the relations as follows:
Flight
(flightnumber (unique), flighttime, airline_id, departure_city, arrival_city, passenger_id, pilot_id, airplane_id)
has_one_and_belongs_to :airline
has_many :passengers
has_one :pilot
Itinerary(passenger_id, flight_id)
Belongs_to
Passenger_details
(passengername (unique), gender, date_of_birth)
has_many :flights
Pilot
(pilotname (unique), gender, date_of_birth)
has_many :flights
airline(airlinename)
airplane(planeID, type, seats))
Explanation:
To normalize a relation, we have to remove any redundancies from the relationships between database objects/tables and simplify the structure. This also means simplifying many-to-many relationships. In this question, we see there is a many-to-many relationship between flights and passengers. To resolve this we can introduce a join table which simplifies this relationship to a one-to-many between the objects.
