Please help! picture above plus, part B: write the quadratic expression in the numerator and the dominator in factored form. Par
t C: cancel the common factor of the numerator and the denominator to write the expression in simplified form.
2 answers:
Answer:
<em>Hi</em><em>,</em><em> </em><em>there</em><em>!</em><em>!</em><em>!</em>
<em>The</em><em> </em><em>answer</em><em> </em><em>would be</em><em> </em><em>2</em><em>(</em><em>2</em><em>x-1</em><em>)</em><em>/</em><em>x</em><em>(</em><em>x-4</em><em>)</em><em>.</em>
<em>See</em><em> </em><em>explanation</em><em> </em><em>in</em><em> </em><em>picture</em><em>.</em><em> </em>
<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em><em><u>.</u></em>
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Answer: D
Step-by-step explanation:
The graph is narrower, so the coefficient of has an absolute value more than 1.
- Eliminate B and C.
Also, because g(x) opens down, the coefficient of is negative.
- Eliminate A.
This leaves D as the answer.
Inequation 1:
to plot the pairs (x, y) for which the inequation holds, draw the line
then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.
we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.
inequation 2:
draw the lines
i) use points (0, -3), (3, -1)
ii)
use points ( 0, 4), (3, 2)
let's use the point P(3, 3) to see what region of the lines need to be coloured:
;
, not true so we color the region not containing this point
not true, so we color the region not containing the point (3, 3)
The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.
to plot the pairs (x, y) for which the inequation holds, draw the line
then pick a point in either side of the line. If that point is a solution of the inequation, than color that region of the line, if that point is not a solution, then color the other part of the line.
we do the same for the second inequation. Then the solution, is the region of the x-y axes colored in both cases.
inequation 2:
draw the lines
i)
ii)
let's use the point P(3, 3) to see what region of the lines need to be coloured:
The graph representing the system of inequalities is the region colored both red and blue, with the blue line not dashed, and the red line dashed.
Answer:
All apply
Step-by-step explanation:
Complementary angles are ones that total 90°. Here, we have two pairs of congruent angles such that each pair totals 90°. We can mix and match to find pairs of complementary angles.
less than 45°: BGC and EGF
more than 45°: AGB and DGE
A complementary pair will consist of one angle from the first list and one angle from the second list. There are 4 possible pairings, and all are shown as answer choices.
All of the choices apply.
