Cobalt has an atomic number (Z) of 27, which means the nuclei of all its isotopes have 27 protons. Cobalt 60 has an atomic mass of 60, so it has 60-27 = 33 neutrons.
The mass of 27 isolated protons plus the mass of 33 isolated neutrons would be:
27*(1.007825 u) + 33*(1.008665 u) = 60.497220 u
The actual mass of the nucleus of 60-Co is 59.933820 u.
Mass defect: 60.497220 u - 59.933820 u = 0.563400 u
The mass defect is equal to the binding energy of a nucleus.
using the fact that 1 u = 931.5 MeV/c^2
(0.563400 u)*(931.5 MeV/u) = 524.807 MeV
Answer: 
Step-by-step explanation:
ALRIGHT ARE YOU READY FOR EPIC MATH TIME?
because i know i am. so lets get this bread.
WATCH: we have 
interesting... that first character is called pi. maybe i should have said, "lets get this pi".
so now lets do some algebra. i am going to work from right to left. lets multiply 6r by 2. that gives us 12r. now we have... 
WE ARE MAKING EPIC PROGRESS, AREN'T WE?
lets multiply 12r by 3r. then we have....

notice how i multiplied 12 by 3 and also r by r (which gives 36 and
respectively)
so your simplified expression is: 
Answer:
1.45
2.61
3.33
4.108
5.98
6.82
7.52
8.142
9.36
10.64
Step-by-step explanation:
Use rule that a straight line is 180 and a right angle is 90
Step-by-step explanation:
11(2y+1)
hope it helps.....