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notsponge [240]
4 years ago
13

To make a batch of sky blue paint, Claire mixes 2 cups of blue paint. Explain how to make a mixture that is a darker shade of bl

ue than sky blue.
Mathematics
1 answer:
alexira [117]4 years ago
8 0
She’s have to mix a little bit of purple and white
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Solve for ALL values of x given the following equation. (Simplify whenever possible) *
professor190 [17]
61:
I think thats what it would be
7 0
4 years ago
What value of x makes this inequality true?<br> x+9 &lt; 4x
wariber [46]

Answer:

X>3

Step-by-step explanation:

X+9<4X

x-x+9<4x-x

9<3x

3<x

6 0
3 years ago
There are only blue ,yellow cubes and green cubes in a bag there are 5 times as many blue cubes as yellow cubes and there are 5
Molodets [167]

Answer:

1 / 31

Step-by-step explanation:

Given that:

Yellow (y) ; Blue (b) ; Green (g)

b = 5y

g = 5b

Assume :

Number of yellow cube = 1

y = 1

b = 5

g = 5*5 = 25

Probability = (required outcome / number of total possible outcomes)

P( picking a yellow) = number of yellow / total number of cubes

Total number of balls = (1 + 5 + 25) = 31

P(picking a yellow) = 1 / 31

7 0
3 years ago
Which of the following are solutions to the equation below?
barxatty [35]

Answer:

x = 3 ± sqrt(11)

Step-by-step explanation:

x^2 - 6x + 9 = 11

Recognizing  that this is a perfect square trinomial

(x-3) ^2 =11

Taking the square root of each side

sqrt((x-3) ^2) = ± sqrt(11)

x-3 =± sqrt(11)

Add 3 to each side

x = 3 ± sqrt(11)

5 0
4 years ago
Read 2 more answers
The total number of students who could attend a field trip is represented by the variable t. The number of students in Group A i
GREYUIT [131]

Answer:

Let's define:

A = # of students in group A

B = # of students in group B

C = # of students in group C.

"The total number of students who could attend a field trip is represented by the variable t."

This can be written as:

A + B + C = t.

"The number of students in Group A is less than the number in Group B."

Here we have a strictly "less than", then this is written as:

A < B.

"Group A has 6 students more than 1/4 the total number of students"

A = t/4 + 6

"Group B has 3 less than the total number of students"

B = t - 3.

Then we have the equations:

A + B + C = t.

A = t/4 + 6

B = t - 3.

A < B.

We could replace the second and third equatio in the fourth one, to get:

t/4 + 6 < t - 3.

t/4 + 9 < t

9 < t - t/4

9 < t*(4/4 - 1/4)

9 < t*(3/4)

(4/3)*9 < t

12 < t.

Then we found an inequality that defines the minimum possible value of t,

4 0
3 years ago
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