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Llana [10]
2 years ago
6

If a sample mean is 92, which of the following is most likely the range of possible values that best describes an estimate for t

he population mean?
A. (80, 112)
B. (82, 114)
C. (76, 108)
D. (78, 110)​
Mathematics
1 answer:
alexdok [17]2 years ago
6 0

Answer:

I think it's c. (76,108)

Step-by-step explanation:

because 76+108 = 184 - half of which is the mean

so c. is more likely

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From a deck of 52 cards, one card is drawn at random. Match the following subsets with their correct probabilities.
zhenek [66]
1.3/13(if you mean jacks queens and kings)
2.1/52
3.1/2
4.1/13
5.1/4
8 0
3 years ago
Read 2 more answers
PLEASEEE HURRYYY
Masteriza [31]

Answer:

(2,-5) and (2,1).

Step-by-step explanation:

We need to find the find all the points having an x coordinate of 2 whose distance from the point (-2,-4) is 5.

A circle with center (-2,-4) and radius 5 represents all the points whose distance from the point (-2,-4) is 5.

Standard form of a circle is

(x-h)^2+(y-k)^2=r^2

where, (h,k) is center and r is the radius.

(x-(-2))^2+(y-(-4))^2=(5)^2

(x+2)^2+(y+2)^2=25

Now, put x=2.

(2+2)^2+(y+2)^2=25

(4)^2+(y+2)^2=25

(y+2)^2=25-16

(y+2)^2=9

Taking square root on both sides.

y+2=\pm\sqrt{9}

y+2=\pm3

y+2=-3\text{ or }y+2=3

y=-5\text{ or }y=1

So, the y-coordinates of the points are -5 and 1.

Therefore, the required points are (2,-5) and (2,1).

8 0
2 years ago
What is the equation of the line that passes through (–2, 3) and is parallel to 2x + 3y = 6?
sergeinik [125]
If they are parallel then the coefficients of x and y will remain the same.  Only the constant will change.

2x + 3y = ?
2(-2) +3(3) = -4 + 9 = 5 so ? is 5

ANSWER: 2x + 3y = 5
6 0
2 years ago
Write the trigonometric expression sin(sin−1u−tan−1v) as an algebraic expression in u and v. Assume that the variables u and v r
igomit [66]

Answer:

[u – v√(1 – u²)]/√(1 + v²)

Step-by-step explanation:

Let sin^-1(u) = A, therefore sinA = u.

We know that sin(theta) = opposite/hypothenuse

Therefore, sinA = u/1 and u is the opposite side to angle A while 1 is the hypotenuse. Draw an acute triangle placing u opposite to angle A and 1 as the hypotenuse. By Pythagoras theorem the adjacent would be √(1 – u²).

By doing this, it means cosA = adjacent/hypotenuse = √(1 – u²)/1 = √(1 – u²)

Also, let tan^-1(v) = B, therefore tanB = v.

We know that tan(theta) = opposite/adjacent

Therefore, tanB = v/1 and v is the opposite side to angle B while 1 is the adjacent. Draw an acute triangle placing v opposite to angle B and 1 as the adjacent. By Pythagoras theorem the hypothenuse would be √(1 + v²).

Therefore, sinB = opposite/hypotenuse = v/√(1 + v²) and cosB = adjacent/hypotenuse = 1/√(1 + v²)

Now,

sin[sin^–1(u) – tan^–1(v)] =

sin(A – B) =

sinAcosB – sinBcosA =

u[1/√(1 + v²)] – [v/√(1 + v²)][√(1 – u²)] =

[u/√(1 + v²)] – [v√(1 – u²)/√1 + v²)] =

[u – v√(1 – u²)]/√(1 + v²).

8 0
2 years ago
An orchard owner wants to plant 64 cherry tree seedlings and 96 peach tree seedlings in rows. Each row is to have the same numbe
-BARSIC- [3]

Answer:

Given:

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peach tree seedlings : 96

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96 / 3 = 32

number of rows

The maximum number of rows that the owner can plant is 32 rows with 2 cherry tree seedlings and 3 peach tree seedlings.

5 0
3 years ago
Read 2 more answers
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