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2 years ago

6

If a sample mean is 92, which of the following is most likely the range of possible values that best describes an estimate for t

he population mean?
A. (80, 112)
B. (82, 114)
C. (76, 108)
D. (78, 110)

1 answer:

alexdok [17]2 years ago

6 0

Answer:

I think it's c. (76,108)

Step-by-step explanation:

because 76+108 = 184 - half of which is the mean

so c. is more likely

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3 years ago

David leaves the house to go to school. He walks 290 m west and 170 m north. To the nearest tenth, how far away is he from his s

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3 years ago

Cuál es el número que no pertenece a esta sucesión 99 koma 105 koma 111 koma 117 koma 123 koma 129 koma 135 koma 141 koma 147 ko

vladimir1956 [14]

Based on the calculations, all of the numbers belong to this arithmetic sequence.

<h3>How to calculate an arithmetic sequence?</h3>

Mathematically, the nth term of an arithmetic sequence can be calculated by using this expression:

$a_n = a_1 +(n-1)d$

<u>Where:</u>

d is the common difference.

a₁ is the first term of an arithmetic sequence.

n is the total number of terms.

Next, we would determine the common difference as follows:

d = a₂ - a₁

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d = 111 - 105 = 6.

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Based on the calculations, all of the numbers belong to this arithmetic sequence.

Read more on arithmetic sequence here: brainly.com/question/12630565

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Complete Question:

What is the number that does not belong to this sequence 99, 105, 111, 117, 123, 129, 135, 141, 147, 153

6 0

2 years ago

Find the vertices and foci of the hyperbola with equation quantity x plus one squared divided by sixteen minus the quantity of y

katrin2010 [14]

Answer:

The vertices are (3 , -5) , (-5 , -5)

The foci are (4 , -5) , (-6 , -5)

Step-by-step explanation:

* Lets study the equation of the hyperbola

- The standard form of the equation of a hyperbola with

center (h , k) and transverse axis parallel to the x-axis is

(x - h)²/a² - (y - k)²/b² = 1

- The length of the transverse axis is 2 a

- The coordinates of the vertices are (h ± a , k)

- The coordinates of the foci are (h ± c , k), where c² = a² + b²

- The distance between the foci is 2c

* Now lets solve the problem

- The equation of the hyperbola is (x + 1)²/16 - (y + 5)²/9 = 1

* From the equation

# a² = 16 ⇒ a = ± 4

# b² = 9 ⇒ b = ± 3

# h = -1

# k = -5

∵ The vertices are (h + a , k) , (h - a , k)

∴ The vertices are (-1 + 4 , -5) , (-1 - 4 , -5)

* The vertices are (3 , -5) , (-5 , -5)

∵ c² = a² + b²

∴ c² = 16 + 9 = 25

∴ c = ± 5

∵ The foci are (h ± c , k)

∴ The foci are (-1 + 5 , -5) , (-1 - 5 , -5)

* The foci are (4 , -5) , (-6 , -5)

4 0

3 years ago

Read 2 more answers

9n - 15 for n = 5 help me please

MaRussiya [10]

If n = 5, then 9n = 45

45 - 15 = 30, which is the same thing as 6n

7 0

3 years ago