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3 years ago

The slopes of LM and HN both equal 0. What can you conclude about the segments

Mathematics

2 answers:

schepotkina [342]3 years ago

5 0

Since the slopes of LM and HN are equal to 0, we can conclude that the segments are parallel.

I hope this helps!

jarptica [38.1K]3 years ago

3 0

I do not know if there are any options, but possible answers could be that they are both parallel, and they are horizontal segments which is why their slopes are 0.

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Salsk061 [2.6K]

0.4 has 4 tenths

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3 years ago

Read 2 more answers

How do you simplify 36 over 10

Studentka2010 [4]

Answer:

18/5

Step-by-step explanation:

36/10

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18 / 5

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3 years ago

Can somebody prove this mathmatical induction?

Flauer [41]

Answer:

See explanation

Step-by-step explanation:

1 step:

n=1, then

$\sum \limits_{j=1}^1 2^j=2^1=2\\ \\2(2^1-1)=2(2-1)=2\cdot 1=2$

So, for j=1 this statement is true

2 step:

Assume that for n=k the following statement is true

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

3 step:

Check for n=k+1 whether the statement

$\sum \limits_{j=1}^{k+1}2^j=2(2^{k+1}-1)$

is true.

Start with the left side:

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}\ \ (\ast)$

According to the 2nd step,

$\sum \limits_{j=1}^k2^j=2(2^k-1)$

Substitute it into the $\ast$

$\sum \limits _{j=1}^{k+1}2^j=\sum \limits _{j=1}^k2^j+2^{k+1}=2(2^k-1)+2^{k+1}=2^{k+1}-2+2^{k+1}=2\cdot 2^{k+1}-2=2^{k+2}-2=2(2^{k+1}-1)$

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4 0

3 years ago

The area of a square rug is 169ft^2. How long is each side of the rug?

jek_recluse [69]

Answer:

$\boxed{ \bold{ \huge{ \boxed{ \sf{13 \: ft}}}}}$

Step-by-step explanation:

$\star{ \sf{ \: Area \: of \: a \: square \: rug \: ( \: A \: ) \: = \: 169 \: {ft}^{2} }}$

$\sf{ \underline{Finding \: the \: length \: of \: a \: square \: ( \: l \: )}}$

$\boxed{ \sf{Area \: of \: a \: square \: = \: {l}^{2} }}$

$\hookrightarrow{ \sf{169 = {l}^{2} }}$

$\hookrightarrow{ \sf{ {l}^{2} = 169}}$

$\hookrightarrow{ \sf{ \sqrt{ {(l)}^{2} } = \sqrt{169} }}$

$\hookrightarrow{ \text{length \: = \: 13 \: ft}}$

$\text{Hope \: I \: helped!}$

$\text{Best \: wishes !!}$

~ $\text{TheAnimeGirl}$

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3 years ago

Find the GCF of the given polynomial.<br><br> 16a4b4 + 32a3b5 - 48a2b6

Anna11 [10]

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3 years ago