\begin{gathered}\{\begin{array}{ccc}3x+5y=2&|\cdot(-3)\\9x+11y=14\end{array}\\\underline{+\{\begin{array}{ccc}-9x-15y=-6\\9x+11y=14\end{array}}\ \ |\text{add both sides of equations}\\.\ \ \ \ \ -4y=8\ \ \ |:(=4)\\.\ \ \ \ \ y=-2\\\\\text{substitute the value of y to the first equation}\\\\3x+5\cdot(-2)=2\\3x-10=2\ \ \ |+10\\3x=12\ \ \ |:3\\x=4\\\\Answer:\ x=4;\ y=-2\to(4;\ -2)\end{gathered}
{
3x+5y=2
9x+11y=14
∣⋅(−3)
−9x−15y=−6
9x+11y=14
add both sides of equations
. −4y=8 ∣:(=4)
. y=−2
substitute the value of y to the first equation
3x+5⋅(−2)=2
3x−10=2 ∣+10
3x=12 ∣:3
x=4
Answer: x=4; y=−2→(4; −2)
The mean is 10 because you will add all the numbers and then divide the answer by 4
Answer:
x = 6, y = -8
Step-by-step explanation:
First we take the equations side by side and put them like this:
6x + 2y = 16
+ 2x - 2y = 32
8x = 48
Then solve for x.
x = 6
Then insert x back into either equation
2(5) - 2y = 32
10 - 2y = 32
solve for y,
y = -10
The answer is to 12 x 12 is 1,524
P(both work) = ((10-3)/10)*((10-3-1)/9) = (7/10)*(6/9) = 42/90
<span>P(at least one does not work) = 1 - P(both work) = 1 - 42/90 = 48/90 = 24/45.</span>
