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labwork [276]
3 years ago
9

Find (ƒ ∙ g)(x) for the functions provided: ƒ(x) = 2x^2, g(x) = (x + 1)^2

Mathematics
2 answers:
bogdanovich [222]3 years ago
5 0
2((x+2)²)² = 2(x+2)^4 = 2x^4 + 16x^3 + 48x^2 + 64x + 32

Hope this helps.
Feliz [49]3 years ago
4 0
The answer is x^4+1 the rest is how I set it up
(2x^2)(x+1)^2=x^4+1
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