Unlike the previous problem, this one requires application of the Law of Cosines. You want to find angle Q when you know the lengths of all 3 sides of the triangle.
Law of Cosines: a^2 = b^2 + c^2 - 2bc cos A
Applying that here:
40^2 = 32^2 + 64^2 - 2(32)(64)cos Q
Do the math. Solve for cos Q, and then find Q in degrees and Q in radians.
Bcbcbcbcbcbcbcbcbcbcbcbcbcbc
3b + 2y = 5g
20g ÷ 5g = 4
4 x 2 = 8
8 oz of yellow paint
Answer:
both 0 is one and c = 1 while d = 4 is another
Step-by-step explanation: