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charle [14.2K]
3 years ago
5

State the domain and range and determine if it's a function?

Mathematics
1 answer:
Dmitriy789 [7]3 years ago
6 0

Answer:

The domain is the set of all "x" values and the range is set of all "y" values in a set of ordered pairs. ... If each x-value corresponds with only one y-value, then the relation is a function.-by-step explanation:

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In a study of government financial aid for college​ students, it becomes necessary to estimate the percentage of​ full-time coll
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Answer:100.     Step-by-step explanation round to to nearest 10

3 0
3 years ago
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Solve -37 n = -56 for n
KIM [24]
<span>-37 n = -56
n=</span>-56/<span>-37
n=56/37 or ~1.51</span>
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3 years ago
Select the correct answer from each drop-down menu.
allochka39001 [22]

Answer:

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6 0
2 years ago
#22-11: Determine the difference in area between circle A and circle B. Use 3.14 for pi.
topjm [15]

Answer:

7.065

Step-by-step explanation:

There are two ways to do this:

(Note: area = pi * r^2)

Method 1:

Diameter of A = 4, so radius = 4/2 = 2

Area of A = 3.14 * 2^2 = 12.56

Diameter of B = 5, so radius = 5/2 = 2.5

Area of B = 3.14 * 2.5^2 = 19.625

Difference in area = 19.625 - 12.56 = 7.065

Method 2:

First find out how much larger the diameter of B is than A, so 5/4 = 1.25.

What this means is if you take the diameter of A and multiply it by 1.25, you get the diameter of B.

When dealing with area, the area of B will be 1.25^2 times bigger than A.

Area of A = 3.14 * 2^2 = 12.56

So area B = 12.56 * 1.25^2 = 19.625

Difference = 19.625 - 12.56 = 7.065

5 0
3 years ago
Find the additive inverse of 6-3i.
puteri [66]
Hey there!

In order to find the additive inverse of any number, regardless if it is real or not, you can simply multiply the number by -1 or negate it.

This should look like this:
-(6-3i)
=-6+3i

Therefore, the additive inverse of 6-3i is -6+3i.

**Note: Keep in mind, when the additive inverse of a number is added to the number, the number equals 0:
(6-3i)+(-6+3i)=0

Hope this helps and have a marvelous day! :)
5 0
3 years ago
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