Select all the expressions that are solutions to 5=23x .

74. A portion of a board has length x feet. The other part has

Novay_Z [31]

Step-by-step explanation:

Given that,

Length of the one portion of the board = x feet
Length of the another portion = (7x – 9) feet

According to the question,

$\longrightarrow$ Total length = Sum of the length of the two pieces

$\longrightarrow$ Total length = {x + (7x – 9)} feet

$\longrightarrow$ Total length = {x + 7x – 9} feet

$\longrightarrow$ Total length = (8x – 9) feet

Therefore, the total length of the board as a simplified expression in x is (8x – 9) feet.

4 0

3 years ago

What is the inverse of the function f(x) = 2x – 10?

VikaD [51]

y = 2x-10 switch x and y x = x = 2y-10 then solve for y 2y = x+10 y = (½)x+5 f⁻¹(x) = (½)x+5 Hope this helps and leave a rate, thanks and brainliest to help me reach expert ;)

8 0

3 years ago

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nter an equation and an answer to the following question: What is the original list price if the discount is $25 and the discoun

castortr0y [4]

Let us set up an equation, to determine the list price. X represents the original price

.12 * x = 25

In order to solve for X, you must divide .12 from both sides

x = 25/.12

After you divide, you should get the number 208.33

25/.12 = 208.33

So, the original list price is $208.33

7 0

2 years ago

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to construct a parallel to a line through a point not on the line using paper folding, you can perform the _____ construction tw

adoni [48]

The correct answer is:

The midpoint of a segment.

Explanation:

To construct a line parallel to another line through a given point, the first thing you do is fold the given line onto itself, making sure that the given point is on the fold. This is the same construction used to find the midpoint of a segment.

Unfold the paper, and the crease made with the fold creates a line through the given point and given line. Fold this new line (crease) onto itself, making sure the given point is in the fold. This is again the same construction used to find the midpoint of a segment, and this creates our parallel line through our given point.

6 0

3 years ago

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Find the volume of the largest rectangular box in the first octant with three faces in the coordinate planes and one vertex in t

nataly862011 [7]

Let (x, y, z) be a point on the plane in the first octant. The box formed by this point has volume xyz, and you want to maximize this subject to the equation of the plane.

Use the method of Lagrange multipliers: the Lagrangian is

L(x, y, z) = xyz - λ (x + 2y + 3z - 6)

Find its critical points:

∂L/∂x = yz - λ = 0

∂L/∂y = xz - 2λ = 0

∂L/∂z = xy - 3λ = 0

∂L/∂λ = -(x + 2y + 3z - 6) = 0

Solving the first three equations for λ gives

λ = yz = xz/2 = xy/3

Solve these equations for y and z :

• yz = xz/2 => y = x/2 => 2y = x

• yz = xy/3 => z = x/3 => 3z = x

Substitute these solutions into the last equation and solve for x, then again for y and z :

x + 2y + 3z - 6 = 3x - 6 = 0 => 3x = 6 => x = 2, y = 1, z = 2/3

At this critical point, the maximum volume is

xyz = 2*1*2/3 = 4/3

4 0

3 years ago