The expected value of the sample mean of the values obtained in these 300 tosses is 3.5
Given :
A fair six sided die is tossed 300 times
We have to find the expected value of the sample mean of the values obtained in these 300 tosses.
A dice have six sides:
In a fair dice every side has equal chance of occurrence,
Now the probability of presence of each side = 1/6
Now the expected value of the sample mean of the values obtained in these 300 tosses is given by:
E(x) = Σx P(x =x)
= 1*1/6 + 2*1/6 + 3*1/6 + 4*1/6 + 5*1/6 + 6*1/6
= 1/6 + 2/6 + 3/6 + 4/6 + 5/6 + 6/6
= 1/6 (1+2+3+4+5+6)
= 1/6 (21)
= 21/6
E(x) = 3.5
Hence, the expected value of the sample mean of the values obtained in these 300 tosses is 3.5
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3 1/3 --> 3 8/24 --> 80/24
6 1/2 --> 6 12/24 --> 156/24
4 1/8 --> 4 3/24 --> 99/24
1 1/4 --> 1 6/24 --> 30/24
About how much more grape juice <u><em>and </em></u>orange juice is used in the punch
80/24+156/24 = 59/6 or 236/24
99/24+30/24= 43/8 or 129/24
236/24-129/24= 107/24 cups OR 4.458 cups OR 4 11/24 cups
About how much more grape juice <u><em>than </em></u>orange juice is used in the punch
3 1/3 --> 3 8/24 --> 80/24
6 1/2 --> 6 12/24 --> 156/24
approximately -3
hope this helps!
An object's dimensions are: length of 25cm, wight of 10cm, and height of 15cm. calculate the object's density if its mass is 3000g
Answer:
Step-by-step explanation:
Supplementary
180-112= 68
alternate exterior
112
