Answer:
C
Explanation:
Chemical formulas are used to describe the types of atoms and their numbers in an element or compound. The atoms of each element are represented by one or two different letters. When more than one atom of a specific element is found in a molecule, a subscript is used to indicate this in the chemical formula.
Cl2 is the answer because we are asked to find the chemical formulae of an element where as the rest H20,NaCl,NH3 are compounds(formed by the bonding of two or more chemical elements ). where as Cl2 is formed by the polar bonds between Cl and Cl atoms hence Cl2 is the chemical formulae of the element chlorine since it exists in that form not as Cl.
<u>Answer:</u> The standard enthalpy change of the reaction is 358.1 kJ
<u>Explanation:</u>
Enthalpy change is defined as the difference in enthalpies of all the product and the reactants each multiplied with their respective number of moles.
The equation used to calculate enthalpy change is of a reaction is:
![\Delta H^o_{rxn}=\sum [n\times \Delta H_f_{(product)}]-\sum [n\times \Delta H_f_{(reactant)}]](https://tex.z-dn.net/?f=%5CDelta%20H%5Eo_%7Brxn%7D%3D%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f_%7B%28product%29%7D%5D-%5Csum%20%5Bn%5Ctimes%20%5CDelta%20H_f_%7B%28reactant%29%7D%5D)
For the given chemical reaction:
![MgCL_2(s)+H_2O(l)\rightarrow MgO(s)+2HCl(g)](https://tex.z-dn.net/?f=MgCL_2%28s%29%2BH_2O%28l%29%5Crightarrow%20MgO%28s%29%2B2HCl%28g%29)
The equation for the enthalpy change of the above reaction is:
![\Delta H_{rxn}=[(1\times \Delta H_f_{(MgO(s))})+(2\times \Delta H_f_{(HCl(g))})]-[(1\times \Delta H_f_{(MgCl_2(s))})+(1\times \Delta H_f_{(H_2O(l))})]](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%281%5Ctimes%20%5CDelta%20H_f_%7B%28MgO%28s%29%29%7D%29%2B%282%5Ctimes%20%5CDelta%20H_f_%7B%28HCl%28g%29%29%7D%29%5D-%5B%281%5Ctimes%20%5CDelta%20H_f_%7B%28MgCl_2%28s%29%29%7D%29%2B%281%5Ctimes%20%5CDelta%20H_f_%7B%28H_2O%28l%29%29%7D%29%5D)
We are given:
![\Delta H_f_{(H_2O(l))}=-285.8kJ/mol\\\Delta H_f_{(MgCl_2(g))}=-641.8kJ/mol\\\Delta H_f_{(MgO(g))}=-384.9kJ/mol\\\Delta H_f_{(HCl(g))}=-92.30kJ/mol](https://tex.z-dn.net/?f=%5CDelta%20H_f_%7B%28H_2O%28l%29%29%7D%3D-285.8kJ%2Fmol%5C%5C%5CDelta%20H_f_%7B%28MgCl_2%28g%29%29%7D%3D-641.8kJ%2Fmol%5C%5C%5CDelta%20H_f_%7B%28MgO%28g%29%29%7D%3D-384.9kJ%2Fmol%5C%5C%5CDelta%20H_f_%7B%28HCl%28g%29%29%7D%3D-92.30kJ%2Fmol)
Putting values in above equation, we get:
![\Delta H_{rxn}=[(1\times (-384.9))+(2\times (-92.30))]-[(1\times (-641.8))+(1\times (-285.8))]\\\\\Delta H_{rxn}=358.1kJ](https://tex.z-dn.net/?f=%5CDelta%20H_%7Brxn%7D%3D%5B%281%5Ctimes%20%28-384.9%29%29%2B%282%5Ctimes%20%28-92.30%29%29%5D-%5B%281%5Ctimes%20%28-641.8%29%29%2B%281%5Ctimes%20%28-285.8%29%29%5D%5C%5C%5C%5C%5CDelta%20H_%7Brxn%7D%3D358.1kJ)
Hence, the standard enthalpy change of the reaction is 358.1 kJ
A) GPS monitoring and satellite imagery of crustal movements
Explanation:
The most recent evidence supporting the theory of plate tectonics is the use of GPS monitoring and satellite imagery of crustal movements.
GPS denotes Global Positioning Systems.
Satellite imagery is a recent advancement in the study of moving plates.
- The global positioning system uses the position of a system of satellites in space to delineate positions on earth.
- It works on the principles of triangulation and this helps to fix positions of objects on the earth surface.
- With this, the change in position of the plates can be recorded by known fixed positions of objects.
- Satellite imagery helps to map changes in terrain with time.
- Images can be correlated through time and the shift in terrains delineated.
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Answer:
Br2+ 2H2O + SO2= 2HBr + H2SO4
Let's Compare the left side of the equation to the right side of the equation.
Left: Br= 2, H= 2, S= 1, O = 1+2
Right: Br=1, H= 1+2, S=1, O= 4
We can see that only S is balanced and not the other 3 elements.
I'll try to make each element balance.
For Br; I'll multiply by 2 on the left to make it equal to the right.
For H; Since the 2 for Br on the right affected also H, that H ( for HBr) Already has a 2, but then it adds with the other H2( for H2SO4) to give a total of 4 H on the right side. But then there's only 2 H on the left. so we multiply that 2 by a 2 ( which is written infront of the H2O to give a total of 4 H on the left side.
For O; Because of the 2 infront of the H2O, it affects the O in H2O..so now we have 2 O plus the 2 O ( in SO2) to give a total of 4 O which is equal to the right side.
Answer:
572. 3 g of NH3
Explanation:
Equation of the reaction: 3H2 + N2 ----> 2NH3
From the equation of reaction, 3 moles of H2 reacts with 1 mole of N2 to produce 2 moles of NH3.
Since N2 is in excess in the given reaction, H2 is the limiting reactant.
Molar mass of H2 = 2 g/mol
Molar mass of NH3 = 17 g/mol
Therefore 3 * 2 g of H2 reacts to produce 2 * 17 g of NH3
6 g of H2 produces 34 g of NH3
101 g of H2 will produce (34 * 101)/6 g of NH3 = 572.3 g of NH3
Therefore, 572.3 g of NH3 are produced