Answer:
HCl is the limiting reactant. It will completely be consumed (1.37 moles)
Option D is correct
Explanation:
Step 1: Data given
Mass of Zinc (Zn) = 50.0 grams
Mass of Hydrogen chloride (HCl) = 50.0 grams
atomic mass Zn = 65.38 g/mol
Molar mass HCl = 36.46 g/mol
Step 2: The balanced equation
Zn + 2HCl → ZnCl2 + H2
Step 3: Calculate moles
Moles = mass / molar mass
Moles Zn = 50.0 grams / 65.38 g/mol
Moles Zn = 0.764 moles
Moles HCl = 50.0 grams / 36.46 g/mol
Moles HCl = 1.37 moles
Step 4: Calculate limiting reactant
For 1 mol Zn we need 2 moles HCl to produce 1 mol ZnCl2 and 1 mol H2
HCl is the limiting reactant. It will completely be consumed (1.37 moles)
Zn is in excess. There will react 1.37/2 = 0.685 moles
There will remain 0.764 -0.685 = 0.079 moles
it is held every 4-5 years
Answer: molar mass
Explanation:
The molar mass of any substance is it's relative molecular mass expressed in grams. Hence, the relationship between molar mass of any substance and mass, in grams, of one mole of any substance is mathematically expressed as:
Number of moles =
(Mass in grams ➗ Molar mass)
Hence, the unit of molar mass is gram per mole (g/mol)
Thus, molar mass is the answer.
The names of the alkanes are 2,2- dimethylbutane, 2,4- dimethylhexane, 2,2,3,3- tetramethylbutane and 4- ethyl, 3,6- dimethyl heptane.
Alkanes are saturated hydrocarbon in the organic chemistry. These are organic compounds that consists of single bonded carbon and hydrogen atoms. The common formula for writing an alkane is given by CₙH₂ₙ₊₂.
Alkanes are further divided into three more types which are:
1. Chain alkanes
2. Cycloalkanes
3. Branched alkanes
Hydrogenation method is used for preparation of alkanes from alkene and alkyne.
The names of the given compounds are:
Part A:
2,2- dimethyl butane
Part B:
2,4- dimethyl hexane
Part C:
2,2,3,3- tetramethyl butane
Part D:
4- ethyl, 3,6- dimethyl heptane
Learn more about alkanes from the link given below.
brainly.com/question/16837399
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Answer:0.286M
Explanation:
10.7g / 149.89g/mol×0.25L
