As,
CuCO₃ ⇆ Cu²⁺ + CO₃²⁻
So,
Kc = [Cu²⁺] [CO₃²⁻] / CuCO₃
Or,
Kc (CuCO₃) = [Cu²⁺] [CO₃²⁻]
Or,
Ksp = [Cu²⁺] [CO₃²⁻]
As,
Ksp = 1.4 × 10⁻¹⁰
So,
1.4 × 10⁻¹⁰ = [x] [x]
Or,
x² = 1.4 × 10⁻¹⁰
Or,
x = 1.18 × 10⁻⁵ mol/L
To cahnge ito g/L,
x = 1.18 × 10⁻⁵ mol/L × 123.526 g/mol
x = 1.45 × 10⁻³ g/L
Answer:
B. Smaller Particles
Explanation:
We know that the rate of reaction increases with increase in the surface area of reactants.
The reacting particles in the log of wood are embedded inside the wood making only very minimal amount of particles available for reaction. This ultimately slows down the rate of combustion.
However, in saw dust, there is a greater availability of surface area of reactants hence the sawdust burns faster than logs.
The yield is 73%. If there is anything that isn’t clear, just send me a message.
Answer: 66.83g
Explanation: (200.59 g/mole = Hg)
0.33 moles = 66.83g
He because nitrogen and ozone is a molecule but helium is atom
