2 years ago

Find dy/dx if y= (cos x) ^ x

1 answer:

5 0

Y = (cos x)^x
log y = log (cos x)^x = x log (cos x)
1/y dy/dx = x * 1/cos x * -sin x + log (cos x) = -xsin x / cos x + log (cos x) = log (cos x) - xtan x
dy/dx = y(log (cos x) - xtan x) = (cos x)^x (log (cos x) - xtan x)

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Evgen [1.6K]

Answer:

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Step-by-step explanation:

AC can be calculated by using Pythagorean Theorem.

Thus:

AC² = AB² + BC²

Plug in the values

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