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marshall27 [118]

2 years ago

15

Gavin had 20 minutes to do a three-problem quiz. He spent 9 9/10 minutes on question A and 3 3/5 minutes on question B. How much

time did he have left for question C?

1 answer:

dalvyx [7]2 years ago

6 0

Answer:

6 1/2 minutes

Step-by-step explanation:

9 9/10 = 9.9

3 3/5 = 3.6

9.9 + 3.6 = 13.5

13.5 = 13 1/2

20 - 13.5 = 6.5 = 6 1/2

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Find the slope of the line that passes through (10, 8) and (9, 13)

7nadin3 [17]

Slope is 5!

Equation:
13-8/9-10=5/1

y2-y1=x2-x1

3 0

2 years ago

When they are both racing on hoverboards, Victoria is 3 times as fast as her brother Max. When she is on foot, she is 3 times sl

NARA [144]

Answer:

Race completed in 48 minutes.

Step-by-step explanation:

Let the speed of Max on hoverboard is = x

Then as per question speed of Victoria on hoverboard = 3x

Now it has been given in the question that speed of Victoria on foot is 1/3 of the speed of Max on hoverboard that will be = x/3

Now we will form the equation.

As we know the formula speed = distance/time

Let the time taken by both to complete the race be t minutes.

Distance covered by Victoria in 12 minutes + Distance covered by Victoria on foot = distance covered by Max on hoverboard

Then the equation will be

12(3x)+(1/3)x(t-12)=xt

$36x+\frac{xt}{3}-4x=xt$

$x(36+\frac{t}{3}-4)=xt$

$36+\frac{t}{3}-4=t$

$32=t-\frac{t}{3}$

$\frac{2t}{3}=32$

$t=\frac{(32)3}{2}=48$

So 48 minutes it took to complete the race.

4 0

2 years ago

Read 2 more answers

Out of 120 students in exam, 2/3 of them passed. How many students passed?

LenKa [72]

Out of 120 students in exam, 2/3 of them passed. How many students passed?

now,

no of students passed = 2/3×120

= 0.66×120

=80...

therefore <em>8</em><em>0</em><em> </em><em> </em><em>students</em><em> </em><em>were</em><em> </em><em>passed</em><em>.</em><em>.</em><em>.</em><em>.</em>

8 0

2 years ago

Read 2 more answers

A number a decreased by 7 is 2.

umka21 [38]

Answer:

9

Step-by-step explanation:

Let's first convert this to numbers. When a number is decreased by a certain amount, that is the same as saying that something is subtracted from it. Therefore:

a-7=2

Add 7 to both sides:

a-7+7=2+7

a=9

Hope this helps!

7 0

2 years ago

Read 2 more answers

Human visual inspection of solder joints on printed circuit boards can be very subjective. Part of the problem stems from the nu

olga_2 [115]

Answer:

a

The probability that the selected joint was judged to be defective by neither of the two inspectors is $P(A' n B' ) = 0.8855$

b

The probability that the selected joint was judged to be defective by inspector B but not by inspector A is $P(A' n B) =0.0403$

Step-by-step explanation:

From the question we are told that

The sample size is $n_s = 10000$

The number of outcome for inspector A is $n__{A}} = 742$

The number of outcome for inspector B is $n__{B}} = 745$

The number of joints judged defective by both inspector is $n(A u B) = 1145$

The the probability that the selected joint was judged to be defective by neither of the two inspectors is mathematically represented as

$P(A' n B' ) = 1 - P(A u B)$

Now

$P(A\ u \ B) = \frac{n(Au B)}{n_s }$

substituting values

$P(A\ u \ B) = \frac{1145}{ 10 000 }$

So

$P(A' n B' ) = 1 - \frac{1145}{10 000}$

$P(A' n B' ) = 0.8855$

the probability that the selected joint was judged to be defective by inspector B but not by inspector A is mathematically represented as

$P(A' n B) = P(A \ u \ B) -P(A)$

Now

$P(A) = \frac{n__{A}}{n_s}$

substituting values

$P(A) = \frac{742}{10 000}$

So

$P(A' n B) = \frac{1145}{10 000} - \frac{742}{10 000}$

$P(A' n B) =0.0403$

7 0

3 years ago