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Rainbow [258]
3 years ago
12

Help me please,Thanks

Mathematics
2 answers:
nalin [4]3 years ago
6 0
There appear to be 13 people with 2/3 sport caps and 6 people with 6/7 sports caps. Just subtract 6 from 13 as shown:
13-6 = 7.
Therefore, 7 more people have 2/3 sports caps than those with 6/7.
Dvinal [7]3 years ago
5 0
The graph shows that 13 friends have 2 or 3 sports caps and that 6 friends have 6 or 7 sports caps.
The question wants you to find the difference between these 2 numbers.
13 - 6 = 7
So there are 7 more friends that have 2 or 3 sports caps than those that have 6 or 7.
You might be interested in
Show that each fn is bounded on A, but the pointwise limit f of the sequence is not bounded on A. Does (fn) converge uniformly t
ladessa [460]

Answer:

It seems your question is not complete, but i will asume it is like the one in the image.

Step-by-step explanation:

Answer at the image

4 0
3 years ago
Daniel goes out to lunch. The bill, before tax and tip, was $14.20. A sales tax of 8% was added on. Daniel tipped 24% on the amo
seraphim [82]

Answer: $19.02

Step-by-step explanation:

First find the sales tax paid. It will be paid on the cost of the meal:

= 14.20 * 8%

= $1.14

Then find the tip which was done after the sales tax was added:

= 24% * (14.20 + 1.14)

= 24% * 15.34

= $3.68

The total cost is:

= Gross amount + Sales tax + tip

= 14.20 + 1.14 + 3.68

= $19.02

3 0
3 years ago
The sale amount is 1,250.00, 5% sales tax.
Marina CMI [18]

Answer:

1250*.05=62.5. Then just add it to the amount for the total dollars shw needs to spend with tax

Step-by-step explanation:

7 0
3 years ago
The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly sel
garri49 [273]

Complete question:

The manager of a supermarket would like to determine the amount of time that customers wait in a check-out line. He randomly selects 45 customers and records the amount of time from the moment they stand in the back of a line until the moment the cashier scans their first item. He calculates the mean and standard deviation of this sample to be barx = 4.2 minutes and s = 2.0 minutes. If appropriate, find a 90% confidence interval for the true mean time (in minutes) that customers at this supermarket wait in a check-out line

Answer:

(3.699, 4.701)

Step-by-step explanation:

Given:

Sample size, n = 45

Sample mean, x' = 4.2

Standard deviation \sigma = 2.0

Required:

Find a 90% CI for true mean time

First find standard error using the formula:

S.E = \frac{\sigma}{\sqrt{n}}

= \frac{2}{\sqrt{45}}

= \frac{2}{6.7082}

SE = 0.298

Standard error = 0.298

Degrees of freedom, df = n - 1 = 45 - 1 = 44

To find t at 90% CI,df = 44:

Level of Significance α= 100% - 90% = 10% = 0.10

t_\alpha_/_2_, _d_f = t_0_._0_5_, _d_f_=_4_4 = 1.6802

Find margin of error using the formula:

M.E = S.E * t

M.E = 0.298 * 1.6802

M.E = 0.500938 ≈ 0.5009

Margin of error = 0.5009

Thus, 90% CI = sample mean ± Margin of error

Lower limit = 4.2 - 0.5009 = 3.699

Upper limit = 4.2 + 0.5009 = 4.7009 ≈ 4.701

Confidence Interval = (3.699, 4.701)

5 0
3 years ago
Cual es el 15% de 36000?
zimovet [89]
15% = 15/100 = 0,15

36000•0,15=5400
4 0
3 years ago
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