3 years ago

18-3+5-12÷4. I am needing help on how to work this problem

Mathematics

1 answer:

AleksandrR [38]3 years ago

8 0

Answer

Step-by-step explanation:

12 divided by 4=3

18-3+5-3

5 minus 3 = 2

18-3+2

18 minus 3 = 15

15+2= 17

answer is 17

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Please help anything helps (if I got the one on the top wrong please tell me :/ )

earnstyle [38]

1 h 3 min+1h 18 min+55 min +68 min= 63 min+78 min +55 min+68 min=
=264 min

264min*1h/60min=4.4 h
correct answer is 3d one

3 0

3 years ago

Read 2 more answers

For which equation is x=5 a solution? Help me please ty :)

VladimirAG [237]

Answer:

B)3x=15

Step-by-step explanation:

3x=15

x=15/3

x=5 (proven)

8 0

3 years ago

shirley is going to have the exterior of her home painted. tims painting charges $250 plus $14 per hour. colorful prints charge

Alexandra [31]

$x-\ number\ of\ hours\\\\
250+14x$

6 0

2 years ago

Find the general solution of (x+3)y’=2y

gregori [183]

Answer:

$y=C(x+3)^2$

Step-by-step explanation:

We are given:

$\displaystyle (x+3)y^\prime=2y$

Separation of Variables:

$\displaystyle \frac{1}{y}\frac{dy}{dx}=\frac{2}{x+3}$

So:

$\displaystyle \frac{dy}{y}=\frac{2}{x+3} \, dx$

Integrate:

$\displaystyle \int\frac{dy}{y}=\int\frac{2}{x+3}\, dx$

Integrate:

$\displaystyle \ln|y|=2\ln|x+3|+C$

Raise both sides to e:

$|y|=e^{2\ln|x+3|+C}$

Simplify:

$|y|=(e^{\ln|x+3|})^2\cdot e^C$

So:

$|y|=C|x+3|^2$

Simplify:

$y=\pm C(x+3)^2=C(x+3)^2$

5 0

3 years ago

If y varies inversely as x, and y = 10 when x = 20,<br> find x when y = 16.

Ipatiy [6.2K]

Answer:

12.5

Step-by-step explanation:

y varies inversely as x.

y = k/x

10 = k/20

200 = k

The constant proportion k is 200.

16 = 200/x

Cross multiply.

200 = 16x

200/16 = x

x = 12.5

5 0

3 years ago