Answer:
11 feet away.
Step-by-step explanation:
Given:
A water and sprinkle our sins water out in a circular pattern
Area formed by the watering pattern is 379.94 square feet
To find:
How many feet away can it spread water means we have to find distance from the middle point to the last end of circular pattern of water sprinkling (radius of a circle) = ?
solution:
By using ,Area of a circle = 
Area of a circle = 379.94 square feet (given)
= 
Dividing both side by 3.14
Taking square root both side
![r = \sqrt[2]{11\times11}](https://tex.z-dn.net/?f=r%20%3D%20%5Csqrt%5B2%5D%7B11%5Ctimes11%7D)
(Taking common)
Therefore, radius = 11
Thus, it can spread water 11 feet away.
The discount is $231.57 , the price after discount would be $283.03
1) We calculate the volume of a metal bar (without the hole).
volume=area of hexagon x length
area of hexagon=(3√3 Side²)/2=(3√3(60 cm)²) / 2=9353.07 cm²
9353.07 cm²=9353.07 cm²(1 m² / 10000 cm²)=0.935 m²
Volume=(0.935 m²)(2 m)=1.871 m³
2) we calculate the volume of the parallelepiped
Volume of a parallelepiped= area of the section x length
area of the section=side²=(40 cm)²=1600 cm²
1600 cm²=(1600 cm²)(1 m² / 10000 cm²=0.16 m²
Volume of a parallelepiped=(0.16 m²)(2 m)=0.32 m³
3) we calculate the volume of a metal hollow bar:
volume of a metal hollow bar=volume of a metal bar - volume of a parallelepiped
Volume of a metal hollow bar=1.871 m³ - 0.32 m³=1.551 m³
4) we calculate the mass of the metal bar
density=mass/ volume ⇒ mass=density *volume
Data:
density=8.10³ kg/m³
volume=1.551 m³
mass=(8x10³ Kg/m³ )12. * (1.551 m³)=12.408x10³ Kg
answer: The mas of the metal bar is 12.408x10³ kg or 12408 kg
Answer: proly like 2
Step-by-step explanation:
Because you have to pay and scan!
9514 1404 393
Answer:
- domain: [-6, -1)
- range: [-5, 4]
Step-by-step explanation:
You have correctly determined the domain to be from x = -6 to x < -1. In interval notation, that would be ...
[-6, -1)
__
The range is the vertical extent of the graph. It extends from a minimum of y = -5 to a maximum of y = +4 at the top of the curve. In interval notation, that would be ...
[-5, 4]
