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aivan3 [116]
3 years ago
7

Find the Difference

Mathematics
1 answer:
Alex777 [14]3 years ago
4 0
The difference of these is 30,10,-10
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HELP ASAP please i cant seem to get out of this question its hard!!!!1111!!!!1!!
zvonat [6]
I think it is A. -7

I think that because FG's distance is 6, and if FG and HI are equal, then their distances should both be equal to 6.
7 0
3 years ago
i need help with questions 12-15. you can choose one but if you can give me all the answers i will mark you brainliest
8090 [49]

For lines to be parallel, the slopes have to be the SAME.

For lines to be perpendicular, the slopes have to be the exact opposite. (opposite sign and number)

For example(perpendicular):

slope is 2

the perpendicular slope is -1/2

slope is -4/5

the perpendicular slope is 5/4


12. line a and b are perpendicular


13. Line a: y = 3/5x + 1

Line b: y = 3/5x - 2/5

Line c: y = 4/6 + 5/3x

line a and b are parallel


14. Line a: y = 3x + 6

Line b: y = 6 - 3x

Line c: y = 2/3x + 6

Neither, none of them are parallel or perpendicular


15. Line a: y = -2/3 + 4/3x

Line b: y = -1/4 - 3/4x

Line c: y = 5 + 3/4x

line a and b are perpendicular

6 0
3 years ago
DATA ANALYSIS AND STATISTICSProbabilities involving two rolls of a dieAn ordinary (falr) die is a cube with the numbers 1 throug
Zepler [3.9K]

Solution

The table below is the required sample space of the to fair die

From the above table

The sample space contain 36 outcomes

Event A: The sum is greater than 9

we will look at the table and count all the elements that are greater than 9

There are 6 elements (they are 10, 10, 10, 11, 11, 12 from the table)

The probability for event A will be

\begin{gathered} p(A)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(A)=\frac{6}{36} \\ p(A)=\frac{1}{6} \end{gathered}

P(A) = 1/6

Event B: The sum is an even number.

We will look at the table and count the number of elements that are even

There are 18 elements (notice that there are 3 even number on each of the 6 rows of the table)

The probability for event B will be

\begin{gathered} p(B)=\frac{\text{required outcome}}{\text{total outcome}} \\ p(B)=\frac{18}{36} \\ p(B)=\frac{1}{2} \end{gathered}

p(B) = 1/2

5 0
1 year ago
Selen had 4 times....
stellarik [79]
I think this is the answer
A)Cathy had $6 at first
B)Selena has $24 at first
3 0
3 years ago
Make B the subject of the relation : 1/a is equal to 1/b + c​
stealth61 [152]

Answer:

By making ‘a’ the subject, I believe you mean isolate the variable ‘a’.

1/a - 1/b = 1/c : add 1/b to both sides

1/a = 1/b + 1/c : combine the unlike fractions by finding a common denominator, bc is the common denominator

1/a = (1/b)(c/c) + (1/c)(b/b) : simplify

1/a = (c/bc) + (b/bc) : add numerators only, because the denominators match

1/a = (c + b)/bc : multiply both sides by a

1 = (a)[(c + b)/bc] : multiply both sides by the reciprocal of [(c + b)/bc] which is [bc/(b + c)]

1[bc/(b + c)] = a

a = bc/(b + c)

This will not work if c = -b, because then you would be dividing by zero.

Example: 1/2 - 1/3 = 1/6 a = 2, b = 3 c= 6

a = bc/(b + c) => 2 = (3 x 6)/(3 + 6) => 2 = 18/9 => 2 = 2.

Step-by-step explanation:

4 0
3 years ago
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