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2 years ago

1. tan a = cot(a + 10°)

Mathematics

1 answer:

Temka [501]2 years ago

7 0

Answer:

$a=40+90n$

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So $\tan(a)=\cot(90-a)$ .

We have the equation:

$\tan(a)=\cot(a+10)$

Make the above replacement:

$\cot(90-a)=\cot(a+10)$

Since cotangent has period 180 degrees, we can also write this as:

$\cot(90-a+180n)=\cot(a+10)$

So solving the following will give us a set of solutions for $a$ :

$90-a+180n=a+10$

Add $a$ on both sides:

$90+180n=2a+10$

Subtract 10 on both sides:

$80+180n=2a$

Divide both sides by 2:

$40+90n=a$

Symmetric property:

$a=40+90n$

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3 years ago

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. Ramu took a loan of 50000 rupees from a bank which charges 10% interest, compounded an- nually. He repaid 10000 rupees after o

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Answer:

= 30,550 rupee owed

Step-by-step explanation:

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2 years ago

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Bret works for a printing company-each document takes 8 sheets of paper-he has 500 sheets-how many documents can he print

Juli2301 [7.4K]

Answer:

He can print 62 documents

Step-by-step explanation:

500/8=62.5

He can print only 62 documents because he cannot print half a document.

Hope this helps!

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7 0

2 years ago

I don’t really get this question so if anyone knows it please help

Mars2501 [29]

Answer:

$116.82\:\text{square inches}$

Step-by-step explanation:

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The area of a triangle is given by $\frac{1}{2}\cdot b\cdot h$ . Since the problem states that the overlapping squares are congruent, both legs of the triangle will be $2.9$ and intersect at a $90^{\circ}$ angle.

Thus, the sum of all four triangles is $\frac{1}{2}\cdot 2.9\cdot 2.9\cdot 4=16.82\:\mathrm{in^2}$ .

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3 years ago

Solve the quadratic equation 3x²-3x-1=0?<br>(by using the square method)

ohaa [14]

Answer:

x=1 and x=-1/3

Step-by-step explanation:

$3x^2-2x-1=0\\\\3(x^2-\frac{2}{3}x-\frac{1}{3})=0\\ \\3(x^2-\frac{2}{3}x-\frac{1}{3}+\frac{4}{9})=3(\frac{4}{9})\\ \\ 3(x^2-\frac{2}{3}x+\frac{1}{9})=\frac{4}{3}\\ \\ 3(x-\frac{1}{3})^2=\frac{4}{3}\\ \\(x-\frac{1}{3})^2=\frac{4}{9}\\ \\x-\frac{1}{3}=\pm\frac{2}{3}$

$x-\frac{1}{3}=\frac{2}{3}\\ \\x=\frac{3}{3}\\ \\x=1$

$x-\frac{1}{3}=-\frac{2}{3}\\ \\x=-\frac{1}{3}$

Therefore, x=1 and x=-1/3

8 0

2 years ago