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antiseptic1488 [7]
3 years ago
12

1. tan a = cot(a + 10°)

Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

a=40+90n

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So \tan(a)=\cot(90-a).

We have the equation:

\tan(a)=\cot(a+10)

Make the above replacement:

\cot(90-a)=\cot(a+10)

Since cotangent has period 180 degrees, we can also write this as:

\cot(90-a+180n)=\cot(a+10)

So solving the following will give us a set of solutions for a:

90-a+180n=a+10

Add a on both sides:

90+180n=2a+10

Subtract 10 on both sides:

80+180n=2a

Divide both sides by 2:

40+90n=a

Symmetric property:

a=40+90n

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