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antiseptic1488 [7]
3 years ago
12

1. tan a = cot(a + 10°)

Mathematics
1 answer:
Temka [501]3 years ago
7 0

Answer:

a=40+90n

Step-by-step explanation:

Use a cofunction identity on the right hand side or left hand side...

So \tan(a)=\cot(90-a).

We have the equation:

\tan(a)=\cot(a+10)

Make the above replacement:

\cot(90-a)=\cot(a+10)

Since cotangent has period 180 degrees, we can also write this as:

\cot(90-a+180n)=\cot(a+10)

So solving the following will give us a set of solutions for a:

90-a+180n=a+10

Add a on both sides:

90+180n=2a+10

Subtract 10 on both sides:

80+180n=2a

Divide both sides by 2:

40+90n=a

Symmetric property:

a=40+90n

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A manufacturer has developed a new fishing line, which the company claims has a mean breaking strength of 15 kilograms with a st
stich3 [128]

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Step-by-step explanation: a) from the question, u= population mean = 15 and x= sample mean = 14.9

σ = population standard deviation = 0.5, n = sample size = 50.

We get the probability of committing a type 1 error by using the z score.

Z = x - u/(σ/√n)

Z = 14.9 - 15/(0.5/√50)

Z = - 0.1/0.0707

Z = - 1.41.

By checking the the probabilistic value attached to this z score using a standard normal distribution table whose area is to the left of the distribution, we have that

P(z=-1.41) = 0.7927.

Hence the probability of committing a type 1 error is 0.7927

b)

at x = 14.8 ( I let ua=x=14.8)

Z = x - u/(σ/√n)

Z = 14.8 - 15/(0.5/√50)

Z = - 0.2/ 0.0707

Z = - 2.83

Using the standard normal distribution table, we have that

P(z=-2.38) = 0.00233.

But α + β = 1

Where α= probability of committing a type 1 error

β = probability of committing a type 2 error.

β = 1 - α

β = 1 - 0.00233

β = 0.99767

At x = 14.9

Z = x - u/(σ/√n)

Z = 14.9 - 15/(0.5/√50)

Z = - 0.1/0.0707

Z = - 1.41.

P(z=-1.41) = 0.7927.

α = 0.7927.

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3 0
3 years ago
Please help with this question
svetlana [45]

Answer:

Segment JK is a chord in circle H

Line LM is a secant to circle H

Step-by-step explanation:

* Lets revise some definition in the circle

- The radius of the circle is a line segment drawn from the center of  

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- The chord of a circle is a line segment whose endpoints lie on the

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- The secant is a line intersect the circle in two points

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∵ Point K lies on the circumference of circle H

∴ Segment JK is a chord in circle H

∵ LM is a line

∵ LM intersect circle H in two points L and M

∴ Line LM is a secant to circle H

4 0
3 years ago
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