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fredd [130]
3 years ago
6

A 4 pound beef loin can be cut into 10 beef chops of equal weight. How many ounces is each beef chop?

Mathematics
1 answer:
11111nata11111 [884]3 years ago
7 0

Answer:

Each beef chop will weigh 0.4 pounds <em><u>6.4 ounces</u></em>

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Add the two expressions. −2.4n−3 and −7.8n+2 Enter your answer in the box. plz help QUICK!!!!!!!!!!
Nikolay [14]
-2.4n-3+-7.8n+2
you combine like terms
(-2.4n+-7.8n)+(-3+2)
= -10.2n-1
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Y = 4x - 1 Simplify and solve when x = 6​
jeyben [28]

Answer:

23

Step-by-step explanation:

6x4 is 24

24-1 is 23

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PLEASE HELP I AM SO CONFUSED
soldi70 [24.7K]

Answer:

Option D, 1

Step-by-step explanation:

<u>Step 1:  Determine what x1, x2, y1, y2 are</u>

Slope = \frac{y2 - y1}{x2-x1}

(x1, y1) is (2, 8)

(x2, y2) is (6, 12)

<u>Step 2:  Plug into the formula to get the slope</u>

Slope = \frac{y2 - y1}{x2-x1}

Slope = \frac{12 - 8}{6 - 2}

Slope = \frac{4}{4}

<em>Slope = 1</em>

<em />

Answer:  Option D, 1

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What are the x and y-intercepts of the line described by the equation?
KiRa [710]

Answer:

x-int (6.2, 0)

y-int (0, 3.1)

Step-by-step explanation:

x-intercept is found when y = 0.

y-intercept is found when x = 0.

Step 1: Define equation

2x + 4y = 12.4

Step 2: Find x-intercept

<em>Substitute y for 0.</em>

2x + 4(0) = 12.4

2x = 12.4

x = 6.2

(6.2, 0)

Step 3: Find y-intercept

<em>Substitute x for 0.</em>

2(0) + 4y = 12.4

4y = 12.4

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(0, 3.1)

6 0
3 years ago
Please find the answer to this function! F(2)= 6x^4-10x^3+40x-50
steposvetlana [31]

<u>Answer-</u>

f(2)= 6x^4-10x^3+40x-50=46

<u>Solution-</u>

The given function is,

\Rightarrow f(x)= 6x^4-10x^3+40x-50

Now, we have to find the value of f(x) at x=2 i.e f(2), so putting x as 2 in the given function,

\Rightarrow f(2)= 6(2)^4-10(2)^3+40(2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

\Rightarrow f(2)= (6\times 16)-(10\times 8)+(40\times 2)-50

\Rightarrow f(2)= 96-80+80-50

\Rightarrow f(2)= 96-50

\Rightarrow f(2)= 46

Therefore, f(2) was found to be 46.


7 0
3 years ago
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