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seraphim [82]
3 years ago
13

CAN YOU HELP ASAP!!!!!!!!!!!!!!!!!!!!!!

Mathematics
1 answer:
love history [14]3 years ago
6 0

Answer:

the square root may be applied only if the constant is positive

Step-by-step explanation:

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Find the slope of the line that passes through K(-4,4), L(5,4)
Sergeu [11.5K]

Answer:

The slope is 0, or it is a zero slope.

Step-by-step explanation:

The y coordinate is 4 throughout, and if it were the x coordinate that stayed the same for both points, it would be a undefined slope.

4 0
3 years ago
Solve using a system of two equations in two unknowns.
vladimir1956 [14]

Hello!

To solve this, first write two equations. We are given two facts about the situation, so we can write the equations accordingly.

Say the length of the rectangle is l, and the width is w.

<u>The length of a rectangle is 9 inches more than twice its width:</u> 2w + 9 = l, as you're adding 9 to two times the width.

<u>The perimeter of the rectangle is 48 inches:</u> The equation for perimeter is 2l + 2w, so we can just use that in this case to make the equation - 2l + 2w = 48

Now, set up the system of equations.

\left \{ {{2w + 9 = l} \atop {2l + 2w = 48}} \right.

Now, we can already use substitution to solve. We get from one of the equations that l = 2w + 9, so we can substitute 2w + 9 for l in the other equation, and then solve for w.

2l + 2w = 48

2 (2w + 9) + 2w = 48

4w + 18 + 2w = 48

6w = 30

w = 5

We know one of our variables now. Now, all that's left to do is substitute 5 for w in one of the original equations to solve for l.

2w + 9 = l

2 (5) + 9 = l

10 + 9 = l

19 = l

Therefore, we now have our dimensions. The length of the rectangle is 19 inches, and the width is 5.

Hope this helps!

4 0
3 years ago
Find all solutions of the equation in the interval (0,2π) <br> cot theta +root 3 = 0
Alisiya [41]

Answer:

θ = 5π/6 rad and 11π/6 rad

Step-by-step explanation:

Given the expression cotθ+√3=0

Subtract √3 from both sides

cotθ+√3-√3=0-√3

cotθ = -√3

Since cotθ = 1/tanθ

1/tanθ = -√3

Reciprocate both sides:

tanθ = -1/√3

θ = tan^-1(-1/√3)

θ = -30°

Since the angle is negative, and tanθ is negative in the second and fourth quadrant.

In the second quadrant;

θ = 180-30

θ = 150°

Since 180° = πrad

150° = 150π/180

150° = 5π/6 rad

In the fourth quadrant;

θ = 360-30

θ = 330°

Since 180° = πrad

330° = 330π/180

330° = 11π/6 rad

Hence the solutions are 5π/6 rad and 11π/6 rad.

7 0
3 years ago
What is the area of rhombus ABCD ?
zimovet [89]
The area is 36 units squared.

You have three ways you can solve this question.

Method 1:

Split the rhombus into two equal triangles.
You will get triangle ACD and triangle ACB.

Count the base length and height length of each triangle using the diagram.
You will get base = 6 units and height = 6 units. Plug this into the area of a triangle and then multiply it by 2.

A = bh/2 * 2
A = 6(6) / 2 * 2
A = 36 / 2 * 2
A = 18 * 2
A = 36

Method 2:

Calculate the length of DP.
The length of line segment DP is √28.8

Calculate the length of DC.
The length of line segment DC is 3√5

Put into equation A = bh.

A = bh
A = 3√5(√28.8)
A = 36

Method 3:

Calculate the length of each diagonal and put into formula A = 1/2(d1 * d2)

Diagonal DB = 12 units
Diagonal AC = 6 units

A = 1/2(d1 * d2)
A = 1/2(12 * 6)
A = 1/2(72)
A = 36

I love procrastinating my history essay for this :D
6 0
3 years ago
Read 2 more answers
Please help a kid out
Vlad1618 [11]

15/24

4 2/3=(4*3)+2/3=14/3

simply 15/24

15/3/24/3=5/8

refine

5/8*14/3

8 and 14 share a factor of 2

8/2=4

14/2=7

refine

5/4*7/3

5*7/4*3

35/12

convert to mixed number

35/12=2.11

2 11/12

the answer is 2 11/12

7 0
4 years ago
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