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Eduardwww [97]
2 years ago
8

The cost (in dollars) of a custom-made sweatshirt is represented by $3.5n+29.99$ , where $n$ is the number of different colors i

n the design. Write a simplified expression that represents the cost of 15 sweatshirts.
Mathematics
1 answer:
Marina86 [1]2 years ago
3 0

Answer:

Cost = 52.5n + 449.85

Step-by-step explanation:

Given

Cost = 3.5n + 29.99

Required

Determine cost of 15

Cost = 3.5n + 29.99

<em>The cost of 15 sweatshirts is calculated by multiplying the cost of 1 by 15.</em>

So, we have:

Cost = (3.5n + 29.99) * 15

Open Brackets

Cost = 3.5n  * 15 + 29.99 * 15

Cost = 52.5n + 449.85

<em>Hence, the simplified cost of 15 sweatshirts is</em>

Cost = 52.5n + 449.85

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Nadia finds out her favorite horse family population is increasing at a constant rate. The horse family was at 24 in 2011 and is
pogonyaev

Answer:

The equation is p = (8/3) t + 24

In 2020, we will have about 48 horses.

Step-by-step explanation:

In 3 years  the family increased by 32 - 24 = 8.

So the  constant of proportionality = 8/3.

The required equation is p = (8/3)tx + 24

where p = the population and t is the number of years after 2011.

So in 2020 we can predict that in 2020 the number of horses

=  (8/3) * 9 + 24

= 72/3 + 24

= 24 + 24

= 48.

4 0
3 years ago
Ajar contains 16 beads. 4 beads are red, 4 are yellow, 5 are green, and 3 are blue.
steposvetlana [31]

Answer:

3/16

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No.of blue beads = 3

Probability of picking a blue bead = 3/16

Step-by-step explanation:

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3 0
3 years ago
Factor the expression using 3 as one factor. 3x−30
posledela

Answer:

3(x - 10)

Step-by-step explanation:

3x - 30 = 3(x - 10)

6 0
3 years ago
What times 2 is equal to 20?
alina1380 [7]
X×2=10 X=10÷2 X=5 Proof: 5×2=10
7 0
3 years ago
Read 2 more answers
Maria is planning to attend UCLA. She is curious what the average age of UCLA students is. Since most students that attend UCLA
RoseWind [281]

Answer:

Yes

We fail to reject the alternative hypothesis Hₐ < 30, that is the average age of students is less than 30

Step-by-step explanation:

Yes because, there is an average age of a sample which can be tested against a null hypotheses

We put

Null hypothesis as H₀ = 30

The alternative hypothesis as Hₐ < 30

We have

z=\frac{\bar{x}-\mu }{\frac{\sigma }{\sqrt{n}}}

With

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μ = 30

σ = 5.2

n = 65

α = 10%

We have

Here we have z = -1.55 and critical z = -1.28

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8 0
3 years ago
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