Hoping to synthesize 3,3-dimethyl-2-butanol, an inexperienced student reacted 3,3-dimethyl-1-butene with H2SO4 / H2O. What major
product was the student surprised to isolate?
1 answer:
Answer:2,3-dimethyl-2-butanol
Explanation:
From the mechanism shown below, the addition of H^+ produces secondary carbocation which is less stable and rearranges by 1,2-alkyl shift to form a more stable tertiary carbocation which onto which the HSO3- now adds. Reaction with water gives the 2,3-dimethyl-2-butanol as the major product. The minor product is 3,3-dimethyl butanol. The alkyl shift is to relieve steric hindrance and create a more stable carbocation.
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Answer:
Hi there!
The correct answer is 2.29 x molecules
Explanation:
To convert from the moles to molecules:
1 mole = 6.022 x 10²³ molecules
so basically you multiply 3.8 by 6.022 x 10²³
and you get: 2.29 x
Answer:
2445 L
Explanation:
Given:
Pressure = 1.60 atm
Temperature = 298 K
Volume = ?
n = 160 mol
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 08206 L.atm/K.mol
Applying the equation as:
1.60 atm × V = 160 mol × 0.08206 L.atm/K.mol × 298 K
<u>⇒V = 2445.39 L</u>
Answer to four significant digits, Volume = 2445 L