Answer:
3.75 L
Explanation:
We can solve this problem by using <em>Charles' law</em>, which states:
Where subscript 1 stands for initial volume and temperature and subscript 2 for final volume and temperature, meaning that in this case:
We <u>input the data</u>:
- 2.5 L * 300 K = V₂ * 200 K
And <u>solve for V₂</u>:
Answer:
[MgSO₄] = 890 mM/L
Explanation:
In order to determine molarity we need to determine the moles of solute that are in 1L of solution.
Solute: MgSO₄ (10.7 g)
Solvent: water
Solution: 100 mL as volume. (100 mL . 1L / 1000mL) = 0.1L
We convert the solute's mass to moles → 10.7 g / 120.36 g/mol = 0.089 moles
Molarity (mol/L) → 0.089 mol/0.1L = 0.89 M
In order to calculate M to mM/L, we make this conversion:
0.89 mol . 1000 mmoles/ 1 mol = 890 mmoles
Answer:
Power
Explanation:
The combined gas law is...
P1V1/T1 = P2V2/T2
These variables stand for pressure, volume, and temperature.
- Hope this helps! If you need a further explanation please let me know.
