Explanation:
For the given compound: (s)-3-iodo-2-methylnonane, only third carbon- atom (marked with red dot) is the chiral atom (as it is attached to 4 different substituents), so the configuration will be assigned to this C-atom only.
In assigning the configuration of this compound, the priorities are assigned based on their atomic masses. The lowest priority group ( that is Hydrogen) should lie on the vertical line. But here, it is lying on the horizontal line, so the configuration will be reversed.
The configuration coming out when H is on the horizontal line is R, but the actual configuration will be S.
The structure of the given organic compound is shown in the image attached.
Strontium atom loses 2 electrons to become an ion with 2 electrons lesser than its atom. Your answer is C.
The answer for the following problem is mentioned below.
- <u><em>Therefore number of molecules(N) present in the calcium phosphate sample are 19.3 × 10^23 molecules.</em></u>
Explanation:
Given:
mass of calcium phosphate (
) = 125.3 grams
We know;
molar mass of calcium phosphate ( ) = (40×3) + 3 (31 +(4×16))
molar mass of calcium phosphate ( ) = 120 + 3(95)
molar mass of calcium phosphate ( ) = 120 +285 = 405 grams
<em>We also know;</em>
No of molecules at STP conditions(
) = 6.023 × 10^23 molecules
To solve:
no of molecules present in the sample(N)
We know;
N÷
=
N =(405×6.023 × 10^23) ÷ 125.3
N = 19.3 × 10^23 molecules
<u><em>Therefore number of molecules(N) present in the calcium phosphate sample are 19.3 × 10^23 molecules</em></u>
