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dimaraw [331]
3 years ago
15

Draw a Lewis Dot Structure for the following element P

Chemistry
1 answer:
Mkey [24]3 years ago
6 0
Lewis dot structure for phosphorus

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A solution is prepared by mixing 25.0 g H2O and 25.0 g C2H5OH. Determine the mole fractions of each substance.
Veronika [31]

Answer:

Mole fraction H₂O → 0.72

Mole fraction C₂H₅OH → 0.28

Explanation:

By the mass of the two elements in the solution, we determine the moles of each:

25 g . 1 mol/ 18g = 1.39 moles of water (solute)

25 g . 1 mol / 46 g = 0.543 moles of ethanol (solvent)

Mole fraction solute = Moles of solute / Total moles

Mole fraction solvent = Moles of solvent / Total moles

Total moles = Moles of solute + Moles of solvent

1.39 moles of solute + 0.543 moles of solvent = 1.933 moles → Total moles

Mole fraction H₂O = 1.39 / 1.933 → 0.72

Mole fraction C₂H₅OH= 0.543 / 1.933 → 0.28

Remember that sum of mole fractions = 1

8 0
3 years ago
Read 2 more answers
Mendeleev arranged the elements by what physical property? atomic number atomic mass boiling point density
m_a_m_a [10]
Mendeleev arranged the elements according to their atomic masses
3 0
3 years ago
Read 2 more answers
Answer the ones please get right
Natali [406]

Answer:

Hope this helps!

Explanation:

I would help you, but I won't. Because you take others people points without helping them and but random words. So, since you are doing that I won't be helping you <3. Thanks for the points idiot.

6 0
3 years ago
Compose a report about three careers in genomics. In your report, answer the following questions:
Rina8888 [55]

Answer:

I don't wanna intrigue but I think this is how you want things to go. But to make it easier all you have to do is look up "what is genomics" and then simply answer each question should take maybe 5-7 minutes. Just trying to help :)

4 0
3 years ago
Calculate the hydrogen-ion concentration [H+] for the aqueous solution in which [OH–] is 1 x 10–11 mol/L. Is this solution acidi
valina [46]
(H+)(OH-) = Kw
kw=  1 x10^-14
OH-=  1   x10 ^-11
(H+)=  KW / OH-

concentration   of H+  = (1x10^-14) /.(1  x 10 ^-11)   =  1  x10  ^-3

Ph=  -log (H+)

PH=-log (  1  x  10  ^-3)  =  3  therefore  the    solution  is  acidic  since  the  PH   less than  7

7 0
3 years ago
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