1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Ipatiy [6.2K]
3 years ago
10

Calculate the number of vacancies per cubic meter for some metal, M, at 773°C. The energy for vacancy formation is 0.97 eV/atom,

while the density and atomic weight for this metal are 7.81 g/cm3 (at 773°C) and 67.81 g/mol, respectively.
Chemistry
1 answer:
Diano4ka-milaya [45]3 years ago
5 0

Answer:

0.112eV/atom

Explanation:

since

p=m/v

then

pv=pv

7.81*0.97=67.81*V

V=7.58/67.81

V= 0.112eV/atom

You might be interested in
Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant o
sattari [20]

Answer:

4.26 %

Explanation:

There is some info missing. I think this is the original question.

<em>Calculate the percent ionization of nitrous acid in a solution that is 0.249 M in nitrous acid. The acid dissociation constant of nitrous acid is  4.50  ×  10 ⁻⁴.</em>

<em />

Step 1: Given data

Initial concentration of the acid (Ca): 0.249 M

Acid dissociation constant (Ka): 4.50  ×  10 ⁻⁴

Step 2: Write the ionization reaction for nitrous acid

HNO₂(aq) ⇒ H⁺(aq) + NO₂⁻(aq)

Step 3: Calculate the concentration of nitrite in the equilibrium ([A⁻])

We will use the following expression.

[A^{-} ] = \sqrt{Ca \times Ka } = \sqrt{0.249 \times 4.50 \times 10^{-4}  } = 0.0106 M

Step 4: Calculate the percent ionization of nitrous acid

We will use the following expression.

\alpha = \frac{[A^{-} ]}{[HA]} \times 100\% = \frac{0.0106M}{0.249} \times 100\% = 4.26\%

4 0
3 years ago
Please answer!! I’ll make brainliest!!
Alenkinab [10]

Answer:

greater than 115 N upwards

Explanation:

3 0
3 years ago
How might you think it is possible to convert from moles to particles or grams to particles?
nevsk [136]

Explanation:

To convert moles to particles or grams to particles, let us have a firm understanding of what a mole is.

A mole is the unit of measuring quantity of particles.

It is the amount of substance that contains the Avogadro's number of particles.

The particle can be atoms, molecules, formula units, electrons, protons, neutrons, etc.

 So, to convert from moles to particles;

    1 mole of a substance  contains 6.02 x 10²³ particles

To convert from grams to particles;

  First convert to moles;

        number of moles  = \frac{mass}{molar mass}  

  So,    1 mole of a substance  contains 6.02 x 10²³ particles

4 0
2 years ago
A 125 g compound consists of 37% oxygen? What is the mass of oxygen in this compound?
zepelin [54]

19.44%

I think that's the anwer

7 0
3 years ago
Green light has a frequency of about 6.00×1014s−1 . What is the energy of a photon of green light?
murzikaleks [220]
3.25 C because I said so and energy is green
8 0
2 years ago
Other questions:
  • What is the density of 35 ml of a liquid that has a mass of 28.7 g?
    12·2 answers
  • An atom's configuration based on its number of electrons ends at 3p3. Another atom has nine more electrons. Starting at 3p, what
    15·2 answers
  • Write ground-state electron configurations for Na+ using a noble gas core abbreviation.
    14·1 answer
  • How many grams are in 2.40 moles of sodium hydroxide (NaOH)?
    12·1 answer
  • What is the name of the compound CrPO4 • 5H2O?
    5·1 answer
  • Determine the molar mass for the element Zn
    11·1 answer
  • A gas has a volume of 5.00 L at 20 degrees Celsius. What is the volume of gas at 150 degrees Celsius.
    14·1 answer
  • If 280.4 g of KOH react with an excess of FeCl3, how many grams of Fe(OH)3 will be produced?
    10·1 answer
  • Plz help!<br><br> What must change in order to change the amount of power?
    8·1 answer
  • What is the mass of 8 moles of sodium (Na) atoms?
    13·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!