Question

A container is at a pressure of 3 atm and a temperature of 280K. What is the new temperature when the pressure is reduced to 1.5 atm.

Answer 1

Answer:

140 K

Explanation:

Step 1: Given data

• Initial pressure of the gas (P₁): 3 atm

• Initial temperature of the gas (T₁): 280 K

• Final pressure of the gas (P₂): 1.5 atm

• Final temperature of the gas (T₂): ?

Step 2: Calculate the final temperature of the gas

We have a gas whose pressure is reduced. If we assume an ideal behavior, we can calculate the final temperature of the gas using Gay-Lussac's law.

T₁/P₁ = T₂/P₂

T₂ = T₁ × P₂/P₁

T₂ = 280 K × 1.5 atm/3 atm = 140 K