Answer:
one atom of an element = 6.02 \times {10}^{23} atom
The mass of one atom of sulphur = 32g
The mass of one atom of aluminium = 27g
so one atom of aluminium = 6.02 \times {10}^{23}
27g of AL = 6.02 \times {10}^{23} atom
2.70g of AL = X atoms
Then you cross multiply ........
and get the answer
.
Q. What type of radioactive decay involves two protons and two neutrons?
A. Alpha emission
Answer:
Explanation:
CaI₂(s) ⟶ Ca²⁺ + 2I⁻
1. Original concentration of I⁻
The chemist diluted 20 mL of the original solution to 100 mL
We can use the dilution formula to calculate the original concentration of I⁻.
2. Original concentration of Ca²⁺
The molar ratio is 1 mol Ca²⁺:2 mol I⁻.
![[\text{Ca}^{2+}] =\dfrac{2.87 \times 10^{-5} \text{ mol I}^{-}}{\text{1 L}} \times \dfrac{\text{1 mol Ca}^{2+} }{\text{2 mol I}^{-}} = \mathbf{1.44 \times 10^{-5}} \textbf{ mol/L}\\\\\text{[Ca$^{2+}$] in the original solution was $\large \boxed{\mathbf{1.44 \times 10^{-5}} \textbf{ mol/L}}$}](https://tex.z-dn.net/?f=%5B%5Ctext%7BCa%7D%5E%7B2%2B%7D%5D%20%3D%5Cdfrac%7B2.87%20%5Ctimes%2010%5E%7B-5%7D%20%5Ctext%7B%20mol%20I%7D%5E%7B-%7D%7D%7B%5Ctext%7B1%20L%7D%7D%20%5Ctimes%20%5Cdfrac%7B%5Ctext%7B1%20mol%20Ca%7D%5E%7B2%2B%7D%20%7D%7B%5Ctext%7B2%20mol%20I%7D%5E%7B-%7D%7D%20%3D%20%5Cmathbf%7B1.44%20%5Ctimes%2010%5E%7B-5%7D%7D%20%5Ctextbf%7B%20mol%2FL%7D%5C%5C%5C%5C%5Ctext%7B%5BCa%24%5E%7B2%2B%7D%24%5D%20in%20the%20original%20solution%20was%20%24%5Clarge%20%5Cboxed%7B%5Cmathbf%7B1.44%20%5Ctimes%2010%5E%7B-5%7D%7D%20%5Ctextbf%7B%20mol%2FL%7D%7D%24%7D)
Answer: Heat is removed as a gas turns into a liquid
Explanation:I took the test
Argon, as all of the ions have 18 electrons.
