Answer: c. At equilibrium, the concentration of reactants is greater than the products
Explanation:
Equilibrium constant for a reaction is the ratio of concentration of products to the concentration of reactants each raised to the power its stoichiometric coefficients.
For the reaction:

Equilibrium constant is given as:
![K_{eq}=\frac{[N_2O_5]}{[NO_2]\times [NO_3]}](https://tex.z-dn.net/?f=K_%7Beq%7D%3D%5Cfrac%7B%5BN_2O_5%5D%7D%7B%5BNO_2%5D%5Ctimes%20%5BNO_3%5D%7D)
![2.1\times 10^{-20}=\frac{[N_2O_5]}{[NO_2]\times [NO_3]}](https://tex.z-dn.net/?f=2.1%5Ctimes%2010%5E%7B-20%7D%3D%5Cfrac%7B%5BN_2O_5%5D%7D%7B%5BNO_2%5D%5Ctimes%20%5BNO_3%5D%7D)
When
a) K > 1, the concentration of products is greater than the concentration of reactants
b) K < 1, the concentration of reactants is greater than the concentration of products
c) K= 1, the reaction is at equilibrium, the concentration of reactants is equal to the concentration of products
Thus as
is
which is less than 1,
the concentration of reactants is greater than the concentration of products
pKa is a value which is related to the acid dissociation constant Ka
pKa = -log Ka
i.e. Ka = 10^-pKa
The deprotonation reaction of acetylene is:
HC≡CH ↔ HC≡C⁻ + H⁺
pKa (HC≡CH) = 25
Solvents with pKa greater than 25 will deprotonate acetylene.
Ans: CH2=CH⁻ pka = 44 and CH3NH⁻ pka = 40
The given question is incomplete. The complete question is:
Calculate the number of moles and the mass of the solute in each of the following solution: 100.0 mL of 3.8 × 10−5 M NaCN, the minimum lethal concentration of sodium cyanide in blood serum
Answer: The number of moles and the mass of the solute are
and
respectively
Explanation:
Molarity of a solution is defined as the number of moles of solute dissolved per liter of the solution.

where,
n = moles of solute
= volume of solution in ml


n = moles of
= 


Thus the number of moles and the mass of the solute are
and
respectively
Explanation:
There are 6.022x1023 molecules in 1 mole of SO3 (Avogadro's number) so in 0.25 moles, there are (0.25)(6.022x1023) molecules in the 0.25 moles of SO3. or 1.506x1023 molecules per 0.25 moles of SO3.
There is one atom of sulfur in each molecule of SO3. So there are 1.506x1023 atoms of sulfur in 0.25 moles of SO3.
1) H2O is able to dissolve both polar molecules and non polar ones
2) due to its extreme polarity it can even dissolve some I onic compounds
3 the h2o molecule itself is small in size