There it is fella tried on ma own consciousness
Total number of Photons = 92.
Radius of the Nucleus = 7.4 x 10^-15 m
Charge of the nucleus = 1.6*10^-19.
Total charge q = 92 x 1.6*10^-19 = 147.2 x 10^-19
k = 9 x 10^9 N m^2 / C^2
Electric field charge E = kq / r^2
=> E = (9 x 10^9 x 147.2 x 10^-19) / (7.4 x 10^-15) ^2
=> (1324.8 x 10^-10) / 54.76 x 10^-30 => 24.19 x 10^20 N/C
Felicia** drove at 45 mph. After 1/3 of an hour, when her husband started out, she was (45/3) = 15 miles from home.
Husband drove at 55 mph. He gained (55-45) = 10 miles on Felicia each hour. That is, he closed 10 miles of the gap each hour.
It took him (15/10) = 1.5 hours to catch up to her.
That's <em>1hr 30min after HE started out</em>, and <em>1hr 50min after SHE left the house</em>.
** I've spelled the wife's name as 'Felicia' throughout my solution. I'm pretty sure there's a better chance of this being the correct spelling rather than 'Felecia', and I never trust anybody who can't spell their own name.
Answer:
22kj
Explanation:
set h = 0 at the end of slide.
final height is -12m
initial condition will be Ui = 0
Ki = 1/2mv² = 1/2 x 61 x (27)² = 22234.5J
Final condition is Ui = mgh = 61 x 9.8 x -12 = -7173J
Ki = 1/2mv²
Ki= 1/2 x 61 x (16)² = 7808J
conservation energy says that
Ui + Ki = Uf +Kf +ΔEth
so ΔEth = Ui + Ki - Uf - Kf
ΔEth = 22234.5 - 7808 + 7173
ΔEth = 21600J
ΔEth =22Kj
Answer:
Explanation:
Energy stored in a capacitor is given by the expression
E = Q² / 2C , where Q is charge on it and C is its capacitance . As we put dielectric slab between the plates , capacitance increases , Due to it energy decreases as capacitance form the denominator in the formula above and Q is constant .
Hence energy decreases.
