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KATRIN_1 [288]
4 years ago
14

The diameter of a 12-gauge copper wire is 0.081 in. The maximum safe current it can 17) carry (in order to prevent fire danger i

n building construction) is 20 A. At this current, what is the drift velocity of the electrons?
Physics
1 answer:
Soloha48 [4]4 years ago
6 0

Answer:

0.44m/s

Explanation:

drift velocity=I/nAq

diameter 12 gauge

wire=0.081inches=0.081*2.5=0.2025cm radius=0.10125cm area=pi*R^2 =20/8.5*10^22*3.14*0.10125^2*10^-4*1.6*10^-19*

V = 0.44m/s

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The boy on the tower throws a ball 20m downrange. What is his pitching speed?
san4es73 [151]

Answer:

The pitching speed of the ball is 19.7 m/s

Explanation:

  • Here, we can use the third equation of motion,  v^{2} = u^{2} - 2as
  • whereas v represents the final velocity, u represents initial velocity, a is the acceleration due to gravity and s is the displacement or distance an object traveled
  • Here, the initial velocity of the the ball is given as  zero and the acceleration due to gravity is 9.8  , the distance 's' is given as 20 m
  • Using the equation,  v^{2} = 2 * 9.8 * 20 = 392\\v = \sqrt{392} = 19.7m/s
  • Hence, the pitching speed of the ball is 19.7 m/s

5 0
3 years ago
Select all of the answers that apply.
postnew [5]
Here are the answers to the given question above.
<span>Relative dating uses laws or principles of stratigraphy and paleontology. These laws of relative dating are: 
-</span><span>law of original horizontality 
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3 0
3 years ago
Read 2 more answers
Consider an electron that is 10-10 m from an alpha particle (9 = 3.2 x 10-19 C). (Enter the magnitudes.) (a) What is the electri
Studentka2010 [4]

Answer:

a)E=2.88*10^{11}N/C

b)E=1.44*10^{11}N/C

c)F=4.61*10^{-8}N

Explanation:

We use the definition of a electric field produced by a point charge:

E=k*q/r^2

<u>a)Electric Field  due to the alpha particle:</u>

E=k*q_{alpha}/r^2=9*10^9*3.2*10^{-19}/(10^{-10})^2=2.88*10^{11}N/C

<u>b)Electric Field  due to electron:</u>

E=k*q_{electron}/r^2=9*10^9*1.6*10^{-19}/(10^{-10})^2=1.44*10^{11}N/C

<u>c)Electric Force on the alpha particle, on the electron:</u>

The alpha particle and electron feel the same force but with opposite direction:

F=k*q_{electron}*q_{alpha}/r^2=9*10^9*1.6*10^{-19}*3.2*10^{-19}/(10^{-10})^2=4.61*10^{-8}N

4 0
3 years ago
Sheila uses a 45N force on her bowling ball across a 15m lane. What work did she do on the bowling ball? Show your work.​
Maurinko [17]

Answer:

675J

Explanation:

Given parameters:

Force  = 45N

Distance  = 15m

Unknown:

Work done by Sheila  = ?

Solution:

Work done by a body is the amount of force applied to make a body move through a distance;

         Work done  = Force x distance

 Now;

          Work done  = 45 x 15  = 675J

6 0
3 years ago
An electron is a particle with a ____.
Dahasolnce [82]

A beta particle. Hoped I help. Sorry if it wrong.

4 0
3 years ago
Read 2 more answers
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