Taking the vertical component of the displacement
1.1 - 0.2 = 0.9 mile
The horizontal component of the displacement
-0.3 mile
The magnitude of the displacement is
√[ (0.9)² + (-0.3) ] = 0.95 mile
The direction is
θ = tan-1 (-0.3/0.9)
θ = 161.57 degrees.
The solution to the problem is as follows:
Normal force is m*g plus 240 N*sin30.
<span>30 kg*9.8 m/s^2 + 240 N*sin30 = 414 N
</span>
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Answer:
The light year is used to measure distances in space because the distances are so big that a large unit of distance is required.
The answer is B) Intentional