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stira [4]
2 years ago
13

The measure of angle A of a triangle is twice the measure of angle B. The measure of angle C is twice the measure of angle A. Wr

ite expressions for angle A and angle C in terms of x for the measure of angle B
Mathematics
2 answers:
zysi [14]2 years ago
8 0

Answer:

In bold below.

Step-by-step explanation:

Let m < B = x.

Then m < A = 2x

and m < C = 2* 2x

m < C = 4x.

Softa [21]2 years ago
4 0
I’m not
Sure sorry :/
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atroni [7]
9-25i is the answer to your question
7 0
3 years ago
Read 2 more answers
You are to take a multiple-choice exam consisting of 64 questions with 5 possible responses to each question. Suppose that you h
damaskus [11]

Answer:

a) Expected score on the exam is 12.8.

b) Variance 10.24, Standard deviation 3.2

Step-by-step explanation:

For each question, there are only two possible outcomes. Either you guesses the answer correctly, or you does not. The probability of guessing the answer of a question correctly is independent of other questions. So we use the binomial probability distribution to solve this question.

Binomial probability distribution

Probability of exactly x sucesses on n repeated trials, with p probability.

The expected value of the binomial distribution is:

E(X) = np

The variance of the binomial distribution is:

V(X) = np(1-p)

The standard deviation of the binomial distribution is:

\sqrt{V(X)} = \sqrt{np(1-p)}

64 questions.

So n = 64

5 possible answers, one correctly, chosen at random:

So p = \frac{1}{5} = 0.2

(a) What is your expected score on the exam?

E(X) = np = 64*0.2 = 12.8

(b) Compute the variance and standard deviation of x. Variance =Standard deviation

V(X) = np(1-p) = 64*0.2*0.8 = 10.24

Variance 10.24

\sqrt{V(X)} = \sqrt{np(1-p)} = \sqrt{64*0.2*0.8} = 3.2

Standard deviation 3.2

5 0
3 years ago
Given h(t)=-2(t+5)2 , find h(-8)
amm1812
The answer I got was 12 if needed I can take a picture of how I worked it

5 0
3 years ago
What is the greatest common factor of 15x^3y^2 and 20x^4y^4?
Vanyuwa [196]
<h3>What is the greatest common factor of 15x³y² and 20x⁴y⁴? ​</h3>

​<em>First we have to find the factors of 15x³y²</em>

<em>15x³y² = 3 * 5x³y² ​</em>

<em>​Then we have to find the factors of 20x⁴y⁴</em>

<em>​20x⁴y⁴ = 2²x¹y² * 5x³y²</em>

<em>Now we have to find the common factors to both numbers.​</em>

<em>The common factors are </em><em>5x³y²</em>

Answer : GCF = (15x³y²,20x⁴y⁴) = 5x³y²​

​Hope this helps!​​​​

​​\textit{\textbf{Spymore}}​​​​​​

6 0
3 years ago
Find the Area of the figure below, composed of an isoceles trapezoid and one
MAVERICK [17]

Answer:

the total area is 15.6 square units

Step-by-step explanation:

hello,

you can  find the total area  dividing the shape into two known shapes

total area= area of the trapezoid +area of the semicircle

then          

step one

find the area of the isosceles trapezoid using

A=\frac{a+b}{2}*h

where

a is the smaller base

b is the bigger base

h is theheight

A is the area

let

a=2

b=5

h=4

put the values into the equation

A=\frac{a+b}{2}*h\\A=\frac{5+2}{2}*4\\A=3.5*4\\A=14

Step two

find the area of the semicircle

the area of a circle is given by

A_{c}=\pi  \frac{d^{2}}{4}\\

but, we need the area of  half circle, we need divide this by 2

A_{semic}=\frac{ \pi \frac{d^{2}}{4}}{2}\\A_{semic}= \pi \frac{d^{2}}{8}

now the diameter of the semicircle is 2, put this value into the equation

A_{semic}= \pi \frac{2^{2}}{8}\\\\A_{semic}= \pi \frac{1}{2}\\ A_{semic}=\frac{\pi }{2}\\

find the total area

total area= area of the trapezoid +area of the semicircle

total\ area= 14+\frac{\pi }{2} \\total\ area=15.6

so, the total area is 15.6 square units

Have a good day.

5 0
3 years ago
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