Answer:
C) 7
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Work Shown:
Use the slope formula
m = (y2-y1)/(x2-x1)
Plug in the given slope we want m = -5/3 and also the coordinates of the points. Then isolate r
m = (y2-y1)/(x2-x1)
-5/3 = (2-r)/(r-4)
-5(r-4) = 3(2-r) .... cross multiplying
-5r+20 = 6-3r
-5r+20+5r = 6-3r+5r .... adding 5 to both sides
20 = 6+2r
20-6 = 6+2r-6 ....subtracting 6 from both sides
14 = 2r
2r = 14
2r/2 = 14/2 .... dividing both sides by 2
r = 7
The slope of the line through (4,7) and (7,2) should be -5/3, let's check that
m = (y2-y1)/(x2-x1)
m = (2-7)/(7-4)
m = -5/3
The answer is confirmed
Answer:
x = 4.75
Step-by-step explanation:
<u>(5 +X</u><u> )/3</u> = 2 - <u> X/4</u>
<h3>
<u>(5 +X</u><u> )/3</u> = 8 - X </h3><h3>5+ X = 3 (8 - X) </h3><h3> 5+ X = 24 - 3X transposing terms</h3><h3>X+ 3X= 24 -5</h3><h3> 4X = 19</h3><h3> X = 19/4 </h3><h3>X = 4.75</h3>
5 to the fifth power or 3125
Answer:
Step-by-step explanation:
The given polynomial is :
p(x) = 5-10x
We need to find the zeros of the above polynomial. To find it, put p(x) = 0
5-10x = 0
Subtract 5 from both sides
5-10x-5=0-5
-10x=-5
or
10x=5
Divide both sides by 10.
x = 0.5 = 1/2
Hence, the zeros of the polynomial is 1/2.
Answer:
The cost of 2 quintal of rice is $10,000.
Step-by-step explanation:
To determine the cost of 2 quintals of rice, knowing that 90 kilos of said product is worth $ 4,500, it is first necessary to establish the equivalence between quintals and kilograms. In this regard, a quintal is equivalent to 100 kilograms, so 2 quintals are equivalent to 200 kilos.
Now, to determine the cost per kilogram of rice, the following calculation is required:
4,500 / 90 = X
50 = X
Therefore, 1 kilogram of rice costs $ 50. Thus, since 200 x 50 equals 10,000, 2 quintals of rice will cost $ 10,000.
