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enot [183]
2 years ago
11

7Bax-ay%7D%20%7D%20-%5Csqrt%7Bx%5E%7B3%7D-x%5E2y%20%7D%20%7D" id="TexFormula1" title="2y\sqrt{x-y} +x\sqrt{\frac{1}{x-y} } -a\sqrt{\frac{a}{ax-ay} } -\sqrt{x^{3}-x^2y } }" alt="2y\sqrt{x-y} +x\sqrt{\frac{1}{x-y} } -a\sqrt{\frac{a}{ax-ay} } -\sqrt{x^{3}-x^2y } }" align="absmiddle" class="latex-formula">
Mathematics
1 answer:
Vsevolod [243]2 years ago
8 0

Answer:

(2y-x)\sqrt{x-y} +(x-a)\sqrt{\frac{1}{x-y} }

Step-by-step explanation:

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Charles is 19 years old. his grandfather is 67 years older than he. what was thee total age 9 years ago?
almond37 [142]
Today: x=19
y=67+19=86

9 years ago: x=19-9=10
y=86-9=77

The total age 9 years ago: x+y=10+77=87
3 0
3 years ago
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Find two integers whose sum is 96 and whose product is 1728.
Murrr4er [49]

Answer: 24 & 72

Step-by-step explanation: 24 + 72 = 96

24 x 72 = 1728

5 0
2 years ago
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A simple random sample of size n=14 is obtained from a population with μ=64 and σ=19.
madam [21]

Answer:

a) A. The population must be normally distributed

b) P(X < 68.2) = 0.7967

c) P(X  ≥  65.6) = 0.3745

Step-by-step explanation:

a) The population is normally distributed having a mean (\mu_x) = 64  and a standard deviation (\sigma_x) = \frac{19}{\sqrt{14} }

b) P(X < 68.2)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x} but μ=64 and σ=19 and n=14,  \mu_x=\mu=64 and \sigma_x=\frac{ \sigma}{\sqrt{n} }=\frac{19}{\sqrt{14} }

Therefore: z=\frac{68.2-64}{\frac{19}{\sqrt{14} } }=0.83

From z table, P(X < 68.2) = P(z < 0.83) = 0.7967

P(X < 68.2) = 0.7967

c) P(X  ≥  65.6)

First me need to calculate the z score (z). This is given by the equation:

z=\frac{x-\mu_x}{\sigma_x}

Therefore: z=\frac{65.6-64}{\frac{19}{\sqrt{14} } }=0.32

From z table,  P(X  ≥  65.6) =  P(z  ≥  0.32) = 1 -  P(z  <  0.32) = 1 - 0.6255 = 0.3745

P(X  ≥  65.6) = 0.3745

P(X < 68.2) = 0.7967

5 0
3 years ago
Who invented the word "book?"
jarptica [38.1K]
Wow!!thats a word from the old english that made it
7 0
2 years ago
Y=52(0.42)^x identify if it's growth or decay and determine the percentage rate of increase or decrease
Shkiper50 [21]

Answer:

58%

Step-by-step explanation:

Given the exponential relation :

Y=52(0.42)^x

Since 0.42 is less than 1, then we can infer that the expression is a Decay function ;

. General form of a exponential function :

y = A(1 - r)^x ; r = Decay rate

Comparing the general equation with the equation given ;

The percentage rate of decrease is obtained thus :

1 - r = 0.42

1 - 0.42 = r

r = 0.58

Rate = 0.58 * 100%

Rate = 58%

4 0
3 years ago
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