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Sloan [31]
4 years ago
7

What is the degree of the power function represented in the table?

Mathematics
2 answers:
Oduvanchick [21]4 years ago
4 0
The answer is 3 i hope this helps
allochka39001 [22]4 years ago
3 0

Answer:

3

Step-by-step explanation:

-2+1= -1

4-3=1

-3/1= -3

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A certain bacterial culture is multiplying in a culture dish, doubling in size every 6 minutes. It takes exactly an hour to fill
Anastaziya [24]
1 hours to fill the dish
for 1/2 of the dish
think
1/2 times 2=2/2=1 so therefor it takes 1 less doubling so

60 mins
1 less double
(double is 6 mins so )
60-6=54
the answe ris 54 mins or a
8 0
3 years ago
A certain car model has a mean gas mileage of 34 miles per gallon (mpg) with a standard deviation A pizza delivery company buys
zubka84 [21]

Answer:

z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028

z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441

An we can use the normal standard table and the following difference and we got this result:

P(-1.028

Step-by-step explanation:

Assuming this statement to complete the problem "with a standard deviation 5 mpg"

We have the following info given:

\mu = 34 represent the mean

\sigma= 5 represent the deviation

We have a sample size of n = 54 and we want to find this probability:

P(33.3 < \bar X< 34.3)

And for this case since the sample size is large enough >30 we can apply the central limit theorem and then we can use this distribution:

\bar X \sim N(\mu , \frac{\sigma}{\sqrt{n}})

And we can use the z score formula given by:

z=\frac{\bar X -\mu}{\frac{\sigma}{\sqrt{n}}}

And replacing we got:

z =\frac{33.3- 34}{\frac{5}{\sqrt{54}}}= -1.028

z =\frac{34.3- 34}{\frac{5}{\sqrt{54}}}= 0.441

An we can use the normal standard table and the following difference and we got this result:

P(-1.028

7 0
4 years ago
Loris dog eats 3.82 pounds of food in one week. how much food will the dog eat in 18 weeks?
shtirl [24]

Answer: the dog eats 68.76 lbs of food in 18 weeks

Step-by-step explanation: 3.82x 18=68.76

6 0
3 years ago
Read 2 more answers
the mean percentage of a population of people eating out at least once a week is 57% with a standard deviation of 3.5 %. assume
zhuklara [117]
Given:
Population proportion, \mu _{p} = 57% = 0.57
Population standard deviation, σ  = 3.5% = 0.035
Sample size, n = 40
Confidence level = 95%

The standard error is
SE_{p} =  \sqrt{ \frac{p(1-p)}{n} } = \sqrt{ \frac{0.57*0.43}{40} } =0.0783

The confidence interval is 
\hat{p} \pm z^{*}SE_{p}
where
\hat{p} = sample proportion
z* = 1.96 at the 95% confidence lvvel

The sample proportion lies in the interval
(0.57-1.96*0.0783, 0.57+1.96*0.0783) = (0.4165, 0.7235)

Answer: Between 0.417 and 72.4), or between (41% and 72%)

8 0
4 years ago
A marble is randomly selected from a bag containing 15 black, 12 white, and 6 clear marbles. Find P(not clear). Round to the nea
dexar [7]
15+12+6= total number of marbles
33= total
Not clear marbles = 15+12 or 27
27 /33
.818181
82 percent
8 0
3 years ago
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