What is the probability that out of 400 babies born, 185 or fewer will be girls?

Multiplying a measure<br> by a scale to produce a<br> reduced or enlarged<br> measure

svetoff [14.1K]

Answer:

we conclude that:

If the scale factor > 1, the image is stretched

If the scale factor < 1, the image is reduced

If the scale factor = 1, the image and object will be congruent

Step-by-step explanation:

A dilation is a transformation which generates an image that is the same shape as the original object but in a different size.

The image can be obtained by multiplying the measure of the original object by a scale factor.

If the scale factor > 1, the image is stretched

If the scale factor < 1, the image is reduced

If the scale factor = 1, the image and object will be congruent

For example, if we multiply the measure of the coordinates of the vertex A(2, 2) of a triangle by a scale factor of 2, the image A' is stretched as the scale factor > 1.

Dilation with scale factor 2, multiply by 2.

(x, y) → (2x, 2y)

A(2, 2) → (2(2), 2(2)) = A'(4, 4)

So, the image point A'(4, 4) is enlarged.

Dilation with scale factor ½, multiply by ½.

(x, y) → (½x, ½y )

A(2, 2) → (2(1/2), 2(1/2)) = A'(1, 1)

So, the image point A'(1, 1) is reduced.

Therefore, we conclude that:

If the scale factor > 1, the image is stretched

If the scale factor < 1, the image is reduced

If the scale factor = 1, the image and object will be congruent

5 0

3 years ago

A store brought a case of disposable cameras for $300. The store's profit p on the cameras is a function of the number c of came

rewona [7]

Answer:

Range: {-300, -210, 0, 72}

Step-by-step explanation:

Given:

Cost price of each camera = $300

The function for profit 'p' is given as:

$p=6c-300$

Where, 'p' is the profit and 'c' is the number of cameras sold.

The domain of the function is: {0, 15, 50, 62}

Now, range is the output of the above function for the given domain.

Here, 'c' is the independent variable and hence the domain.

So, plugging in the values of 'c' in the above function will give the set of values of range.

For $c=0$ , the profit is given as:

$p(0)=6(0)-300\\p(0)=-300$

For $c=15$ , the profit is given as:

$p(15)=6(15)-300\\p(15)=90-300=-210$

For $c=50$ , the profit is given as:

$p(50)=6(50)-300\\p(50)=300-300=0$

For $c=62$ , the profit is given as:

$p(62)=6(62)-300\\p(62)=372-300=72$

Therefore, the range of the given function is: {-300, -210, 0, 72}

The above range represents the profit of the store when 'c' number of cameras are sold. The domain represents the number of cameras that are sold by the store.

So, negative profit means the store has a loss on selling that number cameras.

The store suffers loss upto 50 cameras sold. When the number of cameras sold is 50, there is neither loss not profit. At this point, total cost price equals total selling price. This is also break even point.

After this point, the store will have a net profit. So, for 62 cameras sold, the net profit of the store is $72.

6 0

3 years ago

Find the length of AC to the nearest tenth of a meter. 6pts

joja [24]

Ac is 7 because it is a right angle

4 0

3 years ago

Plss answer my question now i need it this friday

professor190 [17]

Hello! i can do the first word problem

first we need to divide 600/3 which is 200.
therefore we can infer that he does 200 letters an hour and we can solve the problem with this

200 x 7 = 1400 letters an hour

6 0

3 years ago

Q(a+1) - 2q(a) if q(x) = x²+3x+4

siniylev [52]

$q(x) = {x}^{2} + 3x + 4$