Answer :
(2) The work done is, 9.0 J
(3) The power of a machine measures its rate of doing work.
(4) The power used, 700 W
(5) A 750-W motor might also be rated as a 1-horsepower motor.
<u>Solution for part (2) :</u>
Formula used : 
where,
W = work done = ?
F = applied force = 10 N
d = displacement = 0.9 m
Now put all the given values in the above formula, we get the work done.

Therefore, the work done is, 9.0 J
<u>Explanation for part (3) :</u>
Power : it measures the rate of doing work by time.
Formula for power is, 
<u>Solution for part (4) :</u>
Formula used : 
where,
W = work done
F = applied force = 700 N
d = displacement = 6 m
t = time taken = 6 s
Now put all the given values in the above formula, we get the work done.

Therefore, the power used, 700 W
<u>Solution for part (5) :</u>
As, 746 watt is equal to 1 horsepower
So, 750 watt is equal to 
Therefore, a 750-W motor might also be rated as a 1-horsepower motor.