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jek_recluse [69]
3 years ago
11

2. If you exert a force of 10.0 N to lift a box a distance of 0.9 m, how much work have you done?

Physics
2 answers:
KonstantinChe [14]3 years ago
6 0
<span> force of 10.0 N
</span>
<span>distance of 0.9 m
w=f*d
w=10*0.9
=9.0 j</span>
hichkok12 [17]3 years ago
5 0

Answer :

(2) The work done is, 9.0 J

(3) The power of a machine measures  its rate of doing work.

(4) The power used, 700 W

(5) A 750-W motor might also be rated as a  1-horsepower motor.

<u>Solution for part (2) :</u>

Formula used : W=F\times d

where,

W = work done = ?

F = applied force = 10 N

d = displacement = 0.9 m

Now put all the given values in the above formula, we get the work done.

W=(10N)\times (0.9m)}=9J

Therefore, the work done is, 9.0 J

<u>Explanation for part (3) :</u>

Power : it measures the rate of doing work by time.

Formula for power is, Power=\frac{Work}{time}

<u>Solution for part (4) :</u>

Formula used : P=\frac{W}{t}=\frac{F\times d}{t}

where,

W = work done

F = applied force = 700 N

d = displacement = 6 m

t = time taken = 6 s

Now put all the given values in the above formula, we get the work done.

P=\frac{700N\times 6m}{6s}=700W

Therefore, the power used, 700 W

<u>Solution for part (5) :</u>

As, 746 watt is equal to 1 horsepower

So, 750 watt is equal to \frac{750}{746}=1.005=1\text{ horsepower}

Therefore, a 750-W motor might also be rated as a  1-horsepower motor.

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Read 2 more answers
14. a ball is thrown horizontally from the roof of a building 75 m tall with a speed of 4.6 m/s. a. how much later does the ball
Burka [1]

The time taken to hit the ground is 3.9 s, the range is 18m and the final velocity is 42.82 m/s

<h3>Motion Under Gravity</h3>

The motion of an object under gravity is the vertical motion of the object under the influence of acceleration due to gravity.

Given that a ball is thrown horizontally from the roof of a building 75 m tall with a speed of 4.6 m/s.

a. how much later does the ball hit the ground?

The time can be calculated by considering the vertical component of the motion with the use of formula below.

h = ut + 1/2gt²

Where

  • Height h = 75 m
  • Initial velocity u = 0 ( vertical velocity )
  • Acceleration due to gravity g = 9.8 m/s²
  • Time t = ?

Substitute all the parameters into the formula

75 = 0 + 1/2 × 9.8 × t²

75 = 4.9t²

t² = 75/4.9

t² = 15.30

t = √15.3

t = 3.9 s

b. how far from the building will it land?

The range can be found by using the formula

R = ut

Where u = 4.6 m/s ( horizontal velocity )

R = 4.6 × 3.9

R = 18 m

c. what is the velocity of the ball just before it hits the ground?

The final velocity will be

v = u + gt

v = 4.6 + 9.8 × 3.9

v = 4.6 + 38.22

v = 42.82 m/s

Therefore, the answers are 3.9 s, 18 m and 42.82 m/s

Learn more about Vertical motion here: brainly.com/question/24230984

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