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jek_recluse [69]
3 years ago
11

2. If you exert a force of 10.0 N to lift a box a distance of 0.9 m, how much work have you done?

Physics
2 answers:
KonstantinChe [14]3 years ago
6 0
<span> force of 10.0 N
</span>
<span>distance of 0.9 m
w=f*d
w=10*0.9
=9.0 j</span>
hichkok12 [17]3 years ago
5 0

Answer :

(2) The work done is, 9.0 J

(3) The power of a machine measures  its rate of doing work.

(4) The power used, 700 W

(5) A 750-W motor might also be rated as a  1-horsepower motor.

<u>Solution for part (2) :</u>

Formula used : W=F\times d

where,

W = work done = ?

F = applied force = 10 N

d = displacement = 0.9 m

Now put all the given values in the above formula, we get the work done.

W=(10N)\times (0.9m)}=9J

Therefore, the work done is, 9.0 J

<u>Explanation for part (3) :</u>

Power : it measures the rate of doing work by time.

Formula for power is, Power=\frac{Work}{time}

<u>Solution for part (4) :</u>

Formula used : P=\frac{W}{t}=\frac{F\times d}{t}

where,

W = work done

F = applied force = 700 N

d = displacement = 6 m

t = time taken = 6 s

Now put all the given values in the above formula, we get the work done.

P=\frac{700N\times 6m}{6s}=700W

Therefore, the power used, 700 W

<u>Solution for part (5) :</u>

As, 746 watt is equal to 1 horsepower

So, 750 watt is equal to \frac{750}{746}=1.005=1\text{ horsepower}

Therefore, a 750-W motor might also be rated as a  1-horsepower motor.

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our friend is constructing a balancing display for an art project. She has one rock on the left (ms=2.25 kgms=2.25 kg) and three
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Complete Question

The complete question is shown on the first uploaded image

Answer:

a

The torque produced by the pile of rocks is \tau = 35.63\ N \cdot m  

b

The distance of the single for equilibrium to occur is r_s =1.62 \ m

Explanation:

From the question we are told that

     The mass of the left rock is  m_s = 2.25 \ kg

     The mass of the rock on the right m_p = 10.1 kg

    The distance from  fulcrum to the center of the pile of rocks is  r_p = 0.360 \ m

   

Generally the torque produced by the pile of rock is mathematically represented as

           \tau = m_p * g * r_p

Substituting values

         \tau = 10.1 * 9.8  * 0.360                  

          \tau = 35.63\ N \cdot m      

Generally we can mathematically evaluated the distance of the the single rock that would put the system in equilibrium as follows

   The torque due to the single rock is

           \tau = m_s  * g * r_s

At equilibrium the both torque are equal

            35.63 = m_s * r_s * g

Making r_s the subject of the formula

             r_s = \frac{35.63 }{m_s * g}

Substituting values

            r_s = \frac{35.63 }{2.25 * 9.8}

            r_s =1.62 \ m

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15. If an 800.-kg sports car slows to 13.0 m/s to check out an accident scene and the
goldfiish [28.3K]

The final combined velocity after the collision is 20.2 m/s

Explanation:

We can solve this problem by using the law of conservation of momentum: in fact, in absence of external forces, the total momentum of the two car and of the truck must be conserved before and after the collision.

This means that we can write the following equation:

p_i = p_f\\m_1 u_1 + m_2 u_2 = (m_1+m_2)v  

where:  

m_1 = 800 kg is the mass of the sport car

u_1 = 13.0 m/s is the initial velocity of the car (taking its direction as positive  direction)

m_2 = 1200 kg is the mass of the truck

u_2 = 25.0 m/s is the initial velocity of the truck

v is the final combined velocity of the car and the truck, after the collision

Re-arranging the equation and substituting the values, we find the velocity after the collision:

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And the positive sign indicates their final direction is the same as the initial direction of the two vehicles.

Learn more about momentum here:

brainly.com/question/7973509  

brainly.com/question/6573742  

brainly.com/question/2370982  

brainly.com/question/9484203  

#LearnwithBrainly

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